Replace letters using array and preg_replace in PHP

Question

I have the following code:

        $qSeq        = "ATTA";
        $suchmuster  = array("/A/","/T/","/G/","/C/","/U/");
        $ersetzungen = array("T","A","C","G","A");
        $qSeq        = preg_replace($suchmuster, $ersetzungen, $qSeq);
        echo $qSeq;

My aim is that i.e. ATTA becomes TAAT, this logic works fine in Ruby, but PHP will kinda produce AAAA. Any idea how this might work with PHP ?

Tnx!

If your replace may entail changing letters that you've already changed, then use strtr() — Mark Baker
– Mark Baker, Commented Feb 24, 2015 at 14:02

Mark Baker · Accepted Answer · 2015-02-24 14:10:21Z

1

If your replace may entail changing letters that you've already changed, then use strtr()

$qSeq = 'CATGUT';
$suchmuster  = array("A","T","G","C","U");
$ersetzungen = array("T","A","C","G","A");
$qSeq        = strtr($qSeq, array_combine($suchmuster, $ersetzungen));
echo $qSeq;

gives

GTACAA

answered Feb 24, 2015 at 14:10

Mark Baker

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1 Comment

Casimir et Hippolyte Over a year ago

The "first" syntax of strtr seems more appropriate in this case.

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