If statement using every array key

Question

How may I get the following but without manually writing each key? I want the if statement to include every colors key.

if (colors[0].val.join() === colors[colors[0].next].orig.join() &&
    colors[1].val.join() === colors[colors[1].next].orig.join() &&
    colors[2].val.join() === colors[colors[2].next].orig.join() &&
    colors[3].val.join() === colors[colors[3].next].orig.join() &&
    colors[4].val.join() === colors[colors[4].next].orig.join())
{ }

All I can come up with is:

colors.forEach(function(k, i) {
    colors[i].val.join() === colors[colors[i].next].orig.join();
});

Eloims · Accepted Answer · 2015-02-22 22:34:55Z

3

Use the .every() method

if (colors.every(function(el) { return el.val.join() === colors[el.next].orig.join(); })) {
    // do something
}

It will work on every browser, besides IE < 9.

If you need older IE support, polyfill the method (a polyfill is available on the MDN documentation)

answered Feb 22, 2015 at 22:34

Eloims

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1 Comment

David Thomas Over a year ago

Ah, I see; I hadn't seen the property listed in the original question (or I'd glossed over it somehow).

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