Convert code from JavaScript to PHP

Question

My code exist some things like "< i585 >". I wan to get string from "i" to ">". And replace "585" instead of "< i585 >". I write some code in JavaScript.

<script type="text/javascript">
var foo ="M <i585> <i646>";

while (foo.indexOf("<i") != -1) {

    var indexBaş = foo.indexOf("<i");

    var indexSon = foo.indexOf(">", indexBaş);

    var id = foo.substring(indexBaş + 2, indexSon);

    foo = foo.substring(0 , indexBaş) + id + foo.substring(indexSon + 1 , foo.lenght);

}
document.write(foo);
</script>

But I have to convert this code to php. So I write this code

$foo ="M <i585> <i646>";

$start = 0;
$kacTane= 0;

for($i = 0 ; $i < strlen($foo) ; $i++ ) {
    if($foo[$i] == "<") {
        if(($foo + 1 )< strlen($foo)) {
            if($foo[$i+1] == "i") {
                $kacTane++;
            }
        }

    }
}

for($i = 0; $i < $kacTane; $i++) {
    $ilkIndex = strpos($foo , "<" , $start);

    $sonindex = strpos($foo , ">" , $ilkIndex);

    $id = substr($foo , $ilkIndex + 2 ,( $sonIndex -3) - $ilkIndex  );

    $first = substr($foo , 0 , $ilkIndex +2);
    $second = substr($foo , $sonIndex + 1 , strlen($foo) - $sonIndex - 1 );

    $foo = "$first$id$second";
    $start = ($sonindex + 1);

}
echo $foo;

But it isn't work.

Sorry for bad English.

You could make your life easier by creating an array (split on space) and do foreach(). If needed you can convert the array back to string afterwards. — RST
– RST, Commented Feb 19, 2015 at 11:52
I have no time to figure out code now but it sounds like you want to use preg_replace at some point. php.net/manual/en/function.preg-replace.php — Ákos Nikházy
– Ákos Nikházy, Commented Feb 19, 2015 at 11:57
Thank you. But the string can be "M<i656><i578>". I have to find another way. — oznakn
– oznakn, Commented Feb 19, 2015 at 11:58
Change your question and list correct examples otherwise people will not be able to help. — RST
– RST, Commented Feb 19, 2015 at 12:02
you are using a for-loop but not using or increasing $i anywhere. Does this function actually stop? — RST
– RST, Commented Feb 19, 2015 at 12:06

Volvox · Accepted Answer · 2015-02-19 12:30:29Z

1

Maybe some pregmatch?

$foo ="M <i585> <i646>";
preg_match_all('/<i(.*?)>/',$foo, $results); //search for all numbers

$patterns = array();
$replace = array();
foreach ($results[1] as $result){
  $patterns[] = '/<i'.$result.'>/';
  switch ($result) {
    case '585':
      $result = '333';
      break;
    case '646':
      $result = '444';
      break;
  }
  $replace[] = '<i'.$result.'>';
}

$replace = preg_replace($patterns, $replace, $foo); //if you just want to repleace then this single line (+ arrays) are all you need.
echo '<br>'.$replace;

answered Feb 19, 2015 at 12:30

Volvox

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Comments

Jani-B. · Accepted Answer · 2015-02-19 12:24:28Z

There were some typos with the variable names ($sonindex - $sonIndex).

You remove 3 chars from the original string, then before the next iteration you add plus one to the $start, but you should substract one.

$foo ="M <i585> <i646>";
$start = 0;
$kacTane= 0;

for($i = 0 ; $i < strlen($foo) ; $i++ ) {
    if($foo[$i] == "<") {
        if(($foo + 1 )< strlen($foo)) {
             if($foo[$i+1] == "i") {
                $kacTane++;
            }
        }

    }
}

for($i = 0; $i < $kacTane; $i++) {
    $ilkIndex = strpos($foo , "<i" ,$start);

    $sonIndex = strpos($foo , ">" , $ilkIndex);

    $id = substr($foo , $ilkIndex + 2 , $sonIndex  - $ilkIndex -2  );

    $first = substr($foo , 0 , $ilkIndex );
    $second = substr($foo , $sonIndex + 1 , strlen($foo) - $sonIndex - 1 );

    $foo = $first.$id.$second;
    $start = ($sonIndex - 1);
}
echo $foo;

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