Bash assign string to variable and print

Question

This has been driving me mad for the past hour or so. I have four variables, $A, $B, $C, and $D. For simplicity's sake, let's assume that the values in each of those variables is their corresponding letter. I have tried to create a variable to hold a string I'd like to print, like so:

s="${A} failed. ${B} ${C} ${D}"
echo "$s"

I've written a test script exactly like so, and it works perfectly. However, in my actual script, the variables are different.

echo $table_name (prints correctly)
echo $source_count (prints correctly)
echo $disk_size (prints correctly)
echo $hive_count (prints correctly)
s="${table_name} failed. ${source_count} ${disk_size} ${hive_count}" (only prints $disk_size and $hive_count)
echo "$s"

Can anyone think of a reason that $s only seems to store the $disk_size and $hive_count? Is there any character limit to what can be stored in a variable?

Ignacio Vazquez-Abrams · Accepted Answer · 2015-02-11 02:28:22Z

3

$source_count has a CR at the end. Strip it before using the variable.

answered Feb 11, 2015 at 2:28

Ignacio Vazquez-Abrams

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raphnguyen Over a year ago

How can I buy you a beer? Thank you for saving my sanity.

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