I'm trying to create a function that creates a bidimensional array with default values. And then, the function should return the pointer for that static array.
int* novoTabuleiro() {
static int *novoTabuleiro[LINHAS][COLUNAS];
//Some changes
return novoTabuleiro;
}
And then I want to do something like this:
int *tabuleiroJogador = novoTabuleiro();
What is wrong in the function above. The error I receive is "return from incompatible pointer type". Thanks.
Your comments indicate that the array is meant to be a 2-D array of ints:
static int novoTabuleiro[LINHAS][COLUNAS];
return novoTabuleiro;
Due to array-pointer decay, the expression novoTabuleiro in the return statement means the same as &novoTabuleiro[0].
The type of novoTabuleiro[0] is "array [COLUNAS] of int" , i.e. int [COLUNAS]. So a pointer to this is int (*)[COLUNAS].
That means your function needs to be:
int (*func())[COLUNAS] {
and the calling code would be:
int (*tabuleiroJogador)[COLUNAS] = func();
It would be less confusing to use a different name for the function than you use for the name of the array within the function.
You're better off use std::array
static std::array<std::array<int, LINHAS>, COLUNAS> novoTabuleiro;
return novoTabuleiro;
pointer to a static array.. where's that?