I am trying to finish a java program that uploads a file from a client machine to a webserver. The java program is executed with a bat script. I need to pass in a file name to the java program somehow since the filename is different every time. Or can i somehow use %1 instead of the filepath? I dont know.
3 Answers
Why not simply forward the parameters passed to the shell script to the Java application. I usually do something like this:
#!/bin/zsh
java -jar someapp.jar $@
This will pass all the arguments with which the script was executed to the java app and you can act upon them - as far as I understand you need only only - the file path. I'm not familiar with bat scripts, but I assume they have some similar way of passing args around.
answered May 10, 2010 at 21:17
Bozhidar Batsov
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What does the batch file look like that runs the Java program? You can indeed use parameters like this:
java -jar program.jar %1
If you put that line in a file runprogram.bat, then you could run it with:
runprogram somefilename.xyz
and somefilename.xyz will be passed to the Java program as a command line argument.
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No they got it, if i could just pass the filepath as a parameter to the executed jar that would be awesome. Just need to figure out how to pass that parameter into a variable in the program....