How to split string containing numbers into int array i.e
String s="12345";
int i[]=new int[5];
i[0]=1;
i[1]=2;
i[2]=3;
i[3]=4;
i[4]=5;
i have tried it by
String s="12345";
int i[]=new int[5];
int tem = Integer.parseInt(s);
for(int t=0;t<5;t++){
i[4-t]=tem%10;
tem=tem/10;
}
it is giving right answer in above case but in case of String s="73167176531330624919225119674426574742355349194934" it fails so any other way or how to use split method in above case
You can use Character.getNumericValue(char)
String str = "12345";
int[] nums = new int[str.length()];
for (int i = 0; i < str.length(); i++) {
nums[i] = Character.getNumericValue(str.charAt(i));
}
That's because your number wont fit in the integer range nor in long range. Also to note, Your code wont be that efficient due to division and modulas operator as well. Instead you could always use charAt api of String and convert individual characters to a number as give below:
String s = "73167176531330624919225119674426574742355349194934";
int[] numbers = new int[s.length()];
for (int i = 0; i < s.length(); i++) {
numbers[i] = s.charAt(i) - '0';
}
System.out.println(Arrays.toString(numbers));
Output:
[7, 3, 1, 6, 7, 1, 7, 6, 5, 3, 1, 3, 3, 0, 6, 2, 4, 9, 1, 9, 2, 2, 5, 1, 1, 9, 6, 7, 4, 4, 2, 6, 5, 7, 4, 7, 4, 2, 3, 5, 5, 3, 4, 9, 1, 9, 4, 9, 3, 4]
The culprit is this line of code:
int tem = Integer.parseInt(s);
When you enter a large number is string which is outside the range of what an int can accomodate, the overflow happens, and thus all of a sudden you are working on a different number than what was in your string.
I would suggest you iterate over each character of the string, and then convert each character to integer:
for (char ch: s.toCharArray()) {
// convert ch to integer, and add to the array.
intArray[i] = (int)(ch - '0');
// of course keep incrementing `i`
}
split() method would generally be applicable, where you want to split your string based on complex splitter, which involves regex. Here since you just want to read each character, directly getting character array seems appropriate.You can simple use Character wrapper class and get the numeric value and add it to array of in.
String sample = "12345";
int[] result = new int[sample.length()];
for(int i=0;i<result.length;i++)
{
result[i] = Character.getNumericValue(sample.charAt(i));
}
charAt,lengthofString) and-'0'from them. That would give you the numbers which you can store in anint[].