Separate array in sub arrays in C#

Question

I have this following array in C#:

string[][] arrayofArrays = getArray();

I know that the arrays which are in arrayofArrays have a length of 2. My question is the following: is it possible to "split" or to "separate" the principal array in two arrays?

Thanks.

EDIT: I would like to know if there is a way which is already implemented in C#, I know how to do that with an algorithm.

EDIT 2: here is an example of what I need:

// here are the data:
string[][] arrayofArrays = {{"1", "a"}, {"2", "b"}, {"3", "c"}};

//here is what I need as output:
string[] array1 = {"1", "2", "3"};
string[] array2 = {"a", "b", "c"};

You have a 2D array and you want to separate it into 2 single dimension array ? — Rohit
– Rohit, Commented Jan 12, 2015 at 13:15
I would like to know if there is a way which is already implemented in C#, I know how to do that with an algorithm. — Moussamoa
– Moussamoa, Commented Jan 12, 2015 at 13:15
Please could you provide examples of the data returned by the getArray() method and the corresponding expected content of the arrayOfArrays object? — Evil Dog Pie
– Evil Dog Pie, Commented Jan 12, 2015 at 13:18

user4003407 · Accepted Answer · 2015-01-12 13:22:31Z

5

If I understand you right, you can do this:

string[] firstArray=Array.ConvertAll(arrayofArrays,a => a[0]);
string[] secondArray=Array.ConvertAll(arrayofArrays,a => a[1]);

answered Jan 12, 2015 at 13:22

user4003407

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T_D · Accepted Answer · 2015-01-12 13:26:59Z

3

And one more variant:

var array1 = arrayOfArrays.Select(a => a[0]).ToArray();
var array2 = arrayOfArrays.Select(a => a[1]).ToArray();

answered Jan 12, 2015 at 13:26

T_D

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Tim Schmelter · Accepted Answer · 2015-01-12 13:20:31Z

1

For what it's worth, this LINQ query should do what you want:

int numArrays = 2;
string[][] arrayofTwoArrays = arrayofArrays
    .Select((arr, index) => new { arr, index })
    .GroupBy(x => (x.index + 1) % numArrays, x => x.arr)
    .Select(g => g.SelectMany(x => x).ToArray())
    .ToArray();

answered Jan 12, 2015 at 13:20

Tim Schmelter

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