PHP json_decode returns array and NOT an object

Question

I have to do a website with PHP and actually I'm trying with it. For now I want to obtain a JSON from a URL (I've got a web service with Node.js) and show in the screen. The URL returns a JSON object like this:

[{"name":"Juan","text":"Oh my god"},{"name":"Pedro","text":"I'm here"}]

I have this code in PHP file:

<?php 
    $data = file_get_contents('http://localhost:3000/node/busca'); // Returns the JSON
    $terminos = json_decode($data);

    print_r($terminos);

    echo $terminos->name;

?>

But print_r returns:

Array ( 
     [0] => stdClass Object ( 
            [name] => Juan 
            [text] => Oh my god
         ) 
     [1] =>  stdClass Object ( 
            [name] => Pedro
            [text] => I'm here
         )
 )

The echo says

Notice: Trying to get property of non-object in C:...\index.php on line 17

What can I do? json_decode should return an object and not an array.

That's because it is an […] array at the outset. → see — mario
– mario, Commented Jan 8, 2015 at 16:52
Delete what? Are you trying to handle both cases, or something? Did you expect a different data structure? Only want to use one of the entries? Which? Anything else you want to concretize? (For your question here: you can't delete it, once someone answered it.) — mario
– mario, Commented Jan 8, 2015 at 17:01
If you want your script to return one object, fix the script and don't have it return an array. — jeroen
– jeroen, Commented Jan 8, 2015 at 17:02

AbraCadaver · Accepted Answer · 2015-01-08 17:01:56Z

4

The JSON and the decoded PHP is an array of objects. Try:

echo $terminos[0]->name;

You have multiple array elements so:

foreach($terminos as $object) {
    echo $object->name;
}

edited Jan 8, 2015 at 17:01

answered Jan 8, 2015 at 16:52

AbraCadaver

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2 Comments

Hendra Nucleo Over a year ago

Or he can loop it once to get out from the array and directly access the object via $k->name; (assuming $k assigned from foreach) since its stdClass i think?

BGG Over a year ago

This works (with name, sorry) but then, Can't I use print_r? I say, How can I show all the elements?

Joshua Behrens · Accepted Answer · 2015-01-08 16:52:38Z

1

Your data is an encoded array of objects. So you will get an array of objects. Everything is right here.

answered Jan 8, 2015 at 16:52

Joshua Behrens

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Comments

Ryan · Accepted Answer · 2015-01-08 16:56:16Z

1

Edited to OP's question to re-format the array output to:

Array ( 
     [0] => stdClass Object ( 
            [name] => Juan 
            [text] => Oh my god
         ) 
     [1] =>  stdClass Object ( 
            [name] => Pedro
            [text] => I'm here
         )
 )

Looking at it like this it is quite clear how the individual objects are wrapped and addressable:

foreach ($terminos as $idx => $obj ) {
    echo "Name $idx: " $obj->name . PHP_EOL;
    /// ... etc
}

Should output:

Name 0: Juan 
Name 1: Pedro

answered Jan 8, 2015 at 16:56

Ryan

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Comments

C Würtz · Accepted Answer · 2015-01-08 17:01:45Z

0

See json_decode

mixed json_decode ( string $json [, bool $assoc = false [, int $depth = 512 [, int $options = 0 ]]] )


$terminosFalse = json_decode($data, true);
array(2) {
  [0]=>
  array(1) {
    ["attribute"]=>
    string(1) "attr1"
  }
  [1]=>
  array(1) {
    ["attribute"]=>
    string(1) "ATTR2"
  }
}


$terminosTrue = json_decode($data, false);
array(2) {
  [0]=>
  object(stdClass)#1 (1) {
    ["attribute"]=>
        string(1) "attr1"
  }
  [1]=>
  object(stdClass)#2 (1) {
    ["attribute"]=>
    string(1) "ATTR2"
  }
}

edited Jan 8, 2015 at 17:01

answered Jan 8, 2015 at 16:53

C Würtz

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1 Comment

jeroen Over a year ago

That's kind of the opposite of what the OP wants.

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