Python - Launch external program and quit script?

Question

I've wrote a little script to launch a program and send a mail if a program has quit:

#!/usr/bin/env python
# coding: utf8

import psutil    
from email.mime.text import MIMEText
from subprocess import Popen, PIPE
import time
import os

program = "transmission-gtk"
if not program in [psutil.Process(i).name for i in psutil.get_pid_list()]:
   try:
      os.system(program)
      text = "but it has been restarted" 
   except IOError as e:
      text = "The restart failed!\n" + e

   time.sleep(2)

   msg = MIMEText("Transmission has been closed !!\n" + text)
   msg["From"] = "[email protected]"
   msg["To"] = "[email protected]"
   msg["Subject"] = "subject"
   p = Popen(["/usr/sbin/sendmail", "-t"], stdin=PIPE)
   p.communicate(msg.as_string())

The script is launched by cron, every 15 min. All works, except one thing: transmission quit at the same moment the script quits...

I don't want to write a permanent script (raspberry-pi), so a while loop is not what I want.

Then, how to launch my program ?

Pierre · Accepted Answer · 2015-01-15 07:23:18Z

1

You may use os.system(program+'&') to background the execution of your program.

Also, even if your program works, you should have a look at the subprocess module (which intends to replace os.system(), among other things).

edited Jan 15, 2015 at 7:23

answered Dec 25, 2014 at 12:16

Pierre

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1 Comment

Guillaume Over a year ago

Thanks for your response. It was just a problem of Display and environment variable for cron... Anyway, all solutions for this question can be found here

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