example:
var arr = ["a", "b", "c", "d", "e", "f"];
how to check if "a", "b" and "c" are in array?
i tried indexOf() but i cant check if more than 1 strings are in array...
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Did you consider using a "loop"?user663031– user6630312014-12-14 07:49:43 +00:00Commented Dec 14, 2014 at 7:49
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2 Answers
You are use Array.protoype.every and Array.prototype.indexOf, like this
["a", "b", "c"].every(function(currentItem) {
return arr.indexOf(currentItem) !== -1;
});
This will return true, only if all the elements in ["a", "b", "c"] are present in arr.
6 Comments
Irakli Berberashvili
will it be true if there are other strings too in that array?
thefourtheye
@IrakliBerberashvili What do you mean by that? Can you give an example?
seebiscuit
In which browsers is this compatible?
thefourtheye
@Seabiscuit Do you want me to include the list of browsers which do not support these functions?
seebiscuit
At least the earliest iteration of IE browsers that support them. That's usually the bottleneck
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try like this:
var arr = ["a", "b", "c", "d", "e", "f"];
var arr1=['a','b','c'];
for(i=0;i<arr1.length;i++){
var a1 = arr.indexOf(arr1[i]);
console.log(a1);
}
or
var a = arr.indexOf("a");
console.log(a);//0
var b = arr.indexOf("b");
console.log(b);//1
var c = arr.indexOf("c");
console.log(c);//2
