Extract an array out of a multidimensional array in php

Question

I have an multidimensional array in php as follows.

MyArray
(
    [0] => Array
        (
            [id] => c
            [val] => 290
        )

   [2] => Array
        (
            [id] => a
            [val] => 160
        )

   [3] => Array
        (
           [id] => v
           [val] => 150
        )
)

out of this array i want to extract array(c,a,v) I am not able to extract this particular array out of the above multidimensional array. How can i achieve it?

Their keys differ. What is the relationship? Is it always the first element of the sub-array, no matter its key? Please always be as specific as possible with your requirements. Otherwise, answerers are left to guess at your real need. — Michael Berkowski
– Michael Berkowski, Commented Dec 2, 2014 at 15:22

Marcin Twardowski · Accepted Answer · 2014-12-02 15:24:33Z

2

In PHP >= 5.5 you can use array_column()

$letters = array_column($originalArray, 'id');

answered Dec 2, 2014 at 15:24

Marcin Twardowski

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Comments

MH2K9 · Accepted Answer · 2014-12-02 15:43:16Z

2

Suggest you to use array_map().

$your_arr = array(
    array(
        "id" => "c" ,"val" => 290 ),
    array(
        "id" => "a","val" => 160,
    ),
    array(
        "user" => "v","val" => 150,
    )
);

$arr = array_map(function($v){
    return $v['id']; 
}, $your_arr);

print '<pre>';
print_r($arr);
print '</pre>';

Output:

Array
(
    [0] => c
    [1] => a
    [2] => v
)

edited Dec 2, 2014 at 15:43

answered Dec 2, 2014 at 15:23

MH2K9

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Comments

Aleksei Matiushkin · Accepted Answer · 2014-12-02 15:22:35Z

1

Using array_map might help.

array_map(function($elem) { return array_values($elem)[0]; }, $array);

answered Dec 2, 2014 at 15:22

Aleksei Matiushkin

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3 Comments

Michael Berkowski Over a year ago

The value 'v' does not come from a key ['id']

Ajay Ganvir Over a year ago

Hi sorry i just updated my array name. Can you tell me which variable i should replace it with in your code? and in variable the array is returned into?

Aleksei Matiushkin Over a year ago

$array stays for the name of array (the latter variable.)

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