How can i get the number 24 and 200 from the string "Size:24 Resp_code:200"
by using re in python?, i have tried with \d+ but then i only get 24 in addition i have also tried this out:
import re
string2 = " Size:24 Resp_code:200"
regx = "(\d+) Resp_code:(\d+)"
print re.search(regx, string2).group(0)
print re.search(regx, string2).group(1)
here the out put is:
24 Resp_code:200
24
any advice on how to solve this ?
thanks in advance
The group 0 contains the whole matched string. Extract group 1, group 2 instead.
>>> string2 = " Size:24 Resp_code:200"
>>> regx = r"(\d+) Resp_code:(\d+)"
>>> match = re.search(regx, string2)
>>> match.group(1), match.group(2)
('24', '200')
>>> match.groups() # to get all groups from 1 to however many groups
('24', '200')
or using re.findall:
>>> re.findall(r'\d+', string2)
['24', '200']
Use:
print re.search(regx, string2).group(1) // 24
print re.search(regx, string2).group(2) // 200
group(0) prints whole string matched by your regex. Where group(1) is first match and group(2) is second match.
Check the doc:
If there is a single argument, the result is a single string; if there are multiple arguments, the result is a tuple with one item per argument. Without arguments, group1 defaults to zero (the whole match is returned)
You are doing it right but groups don't start at 0, but 1, group(0) will print the whole match:
>>> re.search(regx, string2).group(1,2)
('24', '200')
