Using stored variables with PHP

Question

How to use a stored string which contains a variable?

Example:

I have to gather error notifications strings from the database. These notifications are divided into two types. Regular (common, frequent) strings and targeted (specifically intended) strings.

Let's assume that I have already fetched regular strings and the array was created.

print_r ( $reg_errs );
Array ( [unexp_err] => Array (
  [eng] => An unexpected error has become.
) )

Then I have fetched the array of targeted errors

print_r ( $targ_errs );
Array ( [incorr_cfg_langs] => Array (
  [eng] => $reg_errs['unexp_err']['eng'] . ' Incorrect configuration settings of language versions.'
) )

.

echo $targ_errs['incorr_cfg_langs']['eng'];

The result will be:

$reg_errs['unexp_err']['eng'] . ' Incorrect configuration settings of language versions.'

The requested result is:

An unexpected error has become. Incorrect configuration settings of language versions.

Is there a way to reach my goal? Thank you for any advice ☺

EDIT:

if ( $stmt = $mysqli -> prepare ( "..." ) ) {
    $stmt -> execute ();
    $res = $stmt -> get_result ();
    if ( mysqli_num_rows ( $res ) != NULL ) {
        while ( $row = $res -> fetch_assoc () ) {
            $error = str_replace ( ' ', '', $row['error_assoc_id'] );
            $error_chars_no = mb_strlen ( $error );
            $lang_iso = str_replace ( ' ', '', $row['lang_iso'] );
            $lang_iso_chars_no = mb_strlen ( $lang_iso );
            $value = trim ( $row['value'] );
            $value_chars_no = mb_strlen ( $value );
            if ( ( $error_chars_no >= 3 ) && ( $lang_iso_chars_no == 3 ) && ( $value_chars_no >=3 ) ) {
                $targ_errs[$error][$lang_iso] = $value;
            }
        }
     }
}

}

So you are saying that $reg_errs['unexp_err']['eng'] . ' Incorrect configuration settings of language versions.' is becoming as single string ("$reg_errs['unexp_err']['eng'] . ' Incorrect configuration settings of language versions.'") instead of variable and string concatenation? Are you hiding some code from us? — Justinas
– Justinas, Commented Dec 1, 2014 at 13:27
"An expected error has become" is just the string inside $reg_errs['unexp_err']['eng']. — Manolo
– Manolo, Commented Dec 1, 2014 at 13:30
I have edited echo, there was ['unexp_err'] key and now it is correct. Yes, the result is like you see it in my question and I am not hiding any relevant code. — falcon
– falcon, Commented Dec 1, 2014 at 13:30

Dimag Kharab · Accepted Answer · 2014-12-01 13:34:12Z

2

What about this,

$sp_err = array ( 'unexp_err' => array (
  'eng' => 'An unexpected error has become.'
) );



$reg_err = array ( 'incorr_cfg_langs' => array (
  'eng' => $sp_err['unexp_err']['eng'] . ' Incorrect configuration settings of language versions.'
) );

echo $reg_err['incorr_cfg_langs']['eng'];

answered Dec 1, 2014 at 13:34

Dimag Kharab

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2 Comments

falcon Over a year ago

Thank you for your answer, but it looks like the same what I have now.

AwesomeGuy Over a year ago

This should really work, great PHP, and should work as intended.

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