java.lang.IllegalArgumentException: Illegal character in query at index 59

Question

What i am doing: I am trying to make a reverse geocoding in android

I am getting error as:: java.lang.IllegalArgumentException: Illegal character in query at index 59: http://maps.google.com/maps/api/geocode/json?address=Agram, Bengaluru, Karnataka, India&sensor=false

NOte: that request gets a json response in browser but not from my class below

This line is giving this error::

HttpGet httpget = new HttpGet(url);

JSONfunctions.java

public class JSONfunctions {

    public static JSONObject getJSONfromURL(String url) {
        InputStream is = null;
        String result = "";
        JSONObject jArray = null;

        // Download JSON data from URL
        try {
            HttpClient httpclient = new DefaultHttpClient();
            HttpGet httpget = new HttpGet(url);

            HttpResponse response = httpclient.execute(httpget);
            HttpEntity entity = response.getEntity();
            is = entity.getContent();

        } catch (Exception e) {
            Log.e("log_tag", "Error in http connection " + e.toString());
        }

        // Convert response to string
        try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(
                    is, "iso-8859-1"), 8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }
            is.close();
            result = sb.toString();
        } catch (Exception e) {
            Log.e("log_tag", "Error converting result " + e.toString());
        }

        try {

            jArray = new JSONObject(result);
        } catch (JSONException e) {
            Log.e("log_tag", "Error parsing data " + e.toString());
        }

        return jArray;
    }
}

@laalto ... Can you please show as an answer, i am new to make encoding requests ! — Devrath
– Devrath, Commented Nov 25, 2014 at 12:33

laalto · Accepted Answer · 2014-11-25 12:38:54Z

15

Use URLEncoder.encode() to encode the value of your address parameter "Agram, Bengaluru, Karnataka, India" before putting it in the URL string so that it becomes something like

http://maps.google.com/maps/api/geocode/json?address=Agram,+Bengaluru,+Karnataka,+India&sensor=false

i.e. spaces changed to + and other special octets represented as %xx.

Browsers do smart URL encoding for strings entered in the address bar automatically so that's why it works there.

answered Nov 25, 2014 at 12:38

laalto

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3 Comments

Devrath Over a year ago

When i try that in the respone i am getting as java.lang.IllegalStateException: Target host must not be null, or set in parameters. scheme=null, host=null,

laalto Over a year ago

Don't encode the entire URL, just the value of the parameter that is part of the URL.

Ritesh Gune Over a year ago

laalto that was helpful, thnx.

Akash Moradiya · Accepted Answer · 2014-11-25 12:39:40Z

6

Build your url like,

final StringBuilder request = new StringBuilder(
        "http://maps.googleapis.com/maps/api/geocode/json?sensor=false");
request.append("&language=").append(Locale.getDefault().getLanguage());
request.append("&address=").append(
        URLEncoder.encode(locationName, "UTF-8"));

answered Nov 25, 2014 at 12:39

Akash Moradiya

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Comments

Nirendra Singh Panwar · Accepted Answer · 2017-09-28 05:07:57Z

2

I am using httpclient 4.3.3

String messagestr = "Welcome to Moqui World";
String url="http://my.example.com/api/sendhttp.phpauthkey="+URLEncoder.encode("17djssnvndkfjb110d3","UTF-8")+"&mobiles=91"+URLEncoder.encode(contactNumber,"UTF-8")+"&message="+URLEncoder.encode(messagestr,"UTF8")+"&sender="+URLEncoder.encode("WMOQUI","UTF-8")+"&route=4";

HttpClient client = HttpClientBuilder.create().build();
HttpGet request = new HttpGet(url);
HttpResponse response = client.execute(request);

It's working fine for me. I hope this may help you.

answered Sep 28, 2017 at 5:07

Nirendra Singh Panwar

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