How to get particular values from JSON response by using Android code?

Question

I need to get Particular Object values ( A, B, C, D) and related key values (@"name" ). After getting (A, B, C, D ) object values I need to list out into list view Android. Here below I have posted my sample code and response. Please help me.

@Override
        protected Void doInBackground(Void... arg0) {
            // Creating service handler class instance
            ServiceHandler sh = new ServiceHandler();

            // Making a request to url and getting response
            String jsonStr = sh.makeServiceCall(url, ServiceHandler.GET);
            Log.d("Response: ", "> " + jsonStr);

            if (jsonStr != null) {
                try {
                    JSONObject jsonObj = new JSONObject(jsonStr);

                    contacts = jsonObj.getJSONArray("response");
                    Log.d("Response: ", "> " + contacts);

                    // looping through All Contacts
                    for (int i = 0; i < contacts.length(); i++) {
                        JSONObject c = contacts.getJSONObject(i);

                    }
                } catch (JSONException e) {
                    e.printStackTrace();
                }
            } else {
                Log.e("ServiceHandler", "Couldn't get any data from the url");
            }

            return null;
        }

My JSON Response :

{"response" : [  {

                "A"   :  [   {  
                         "name" : "tango" 
                           },
                       {
                        "name" : "ping"
                       }
                     ],

                "B"  :  [   {  
                         "name" : "tango" 
                           },
                       {
                        "name" : "ping"
                       }
                    ]
             } ]}

I want to get (A, B , C, D) objects from reponse and get first index Name value then list out A and Name, B and Name,... — Ben
– Ben, Commented Nov 10, 2014 at 6:29
@Mano there is no key for JSONObject inside response JSONArray is this ok ? — Kaushik
– Kaushik, Commented Nov 10, 2014 at 6:53

Kaushik · Accepted Answer · 2014-11-11 15:08:23Z

4

Use JSONObject keys() to get the key and then iterate each key to get to the dynamic value.

You can get dynamic keys like this

JSONObject responseDataObj = new JSONObject(responseData);
JSONArray responseArray = responseDataObj.getJSONArray("response");
for (int i = 0; i < responseArray.length(); i++) {
    nodes = new ArrayList<ArrayList<String>>();//nodes ArrayList<ArrayList<String>> declared globally
    nodeSize = new ArrayList<Integer>();//nodeSize ArrayList<Integer> declared globally
    JSONObject obj = responseArray.getJSONObject(i);
    Iterator keys = obj.keys();
    while(keys.hasNext()) {
       // loop to get the dynamic key
       String currentDynamicKey = (String)keys.next();
       //store key in an arraylist which is A,B,...
       // get the value of the dynamic key
       JSONArray currentDynamicValue = obj.getJSONArray(currentDynamicKey);
       int jsonrraySize = currentDynamicValue.length();
       int sizeInArrayList = jsonrraySize + 1;
       nodeSize.add(sizeInArrayList);
       if(jsonrraySize > 0) {
           for (int ii = 0; ii < jsonrraySize; ii++) {
                nameList = new ArrayList<String>();//nameList ArrayList<String> declared globally
               if(ii == 0) {
                JSONObject nameObj = currentDynamicValue.getJSONObject(ii);
                String name = nameObj.getString("name");
                System.out.print("Name = " + name);
                //store name in an arraylist
                nameList.add(name);
              }
           }                    
       }
     nodes.add(nameList);
    }
}

edited Nov 11, 2014 at 15:08

answered Nov 10, 2014 at 7:09

Kaushik

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10 Comments

Ben Over a year ago

Wow Great.. This is I am expected absolute Answer.... Thank you so much @Kaushik....I need to list out A B C vlaues into the list view...

Kaushik Over a year ago

store that in last for loop

Ben Over a year ago

@kaushik...I need another one clarification. Here the code I can get A, B , C values with related name values. But there multiple name values available within A and B. This time I need to get A & B of first index name value only. Please clarify this doubt....

Kaushik Over a year ago

@Mano : u need only 1st name from both A and B

Kaushik Over a year ago

check the edit though I used ArrayList<ArrayList<String>> it is better if u use a ArrayList of POJO class

|

Ketan Ahir · Accepted Answer · 2014-11-10 06:29:09Z

0

You can use following method to parse your response and handle output as per requirement.

private void parseJson(String res) {
    try {
        JSONObject mainObject = new JSONObject(res);
        JSONArray response = mainObject.getJSONArray("response");
        for (int i = 0; i < response.length(); i++) {
            JSONObject obj = response.getJSONObject(i);

            JSONArray A = obj.getJSONArray("A");

            for (int j = 0; j < A.length(); j++) {
                JSONObject objA = A.getJSONObject(j);
                String name = objA.getString("name");
                // use or store name here
            }

            JSONArray B = obj.getJSONArray("B");

            for (int k = 0; k < B.length(); k++) {
                JSONObject objB = B.getJSONObject(k);
                String name = objB.getString("name");
                // use or store name here
            }
        }
    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

}

answered Nov 10, 2014 at 6:29

Ketan Ahir

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3 Comments

Ben Over a year ago

Thanks for your Quick replay @KetanAhir. BTW the problem is we dont know That object is A, B,C,... There some chances for changing other values.... I cant specify the object name A , B, C, ...Particularly...

Ketan Ahir Over a year ago

here A,B,C are array..so it must be known.

Ben Over a year ago

No. I just posted sample response. I cant specify particularly A,B,C... Because I have received different type of names...

Harsh Parikh · Accepted Answer · 2014-11-10 06:34:23Z

0

This may work for you :

        String jsonStr = sh.makeServiceCall(url, ServiceHandler.GET);
        Log.d("Response: ", "> " + jsonStr);
            if (jsonStr != null) {
                try {
                    JSONObject jsonObj = new JSONObject(jsonStr);
                    JSONArray contacts;
                    contacts = jsonObj.getJSONArray("response");
                    Log.d("Response: ", "> " + contacts);

                    // looping through All Contacts
                    for (int i = 0; i < contacts.length(); i++) {
                        JSONObject c = contacts.getJSONObject(i);
                        JSONArray jsonArrayA=new JSONArray();
                        jsonArrayA=c.getJSONArray("A");
                        for(int j=0;j<jsonArrayA.length();j++){
                            String name=jsonArrayA.getJSONObject(j).getString("name");
                            Log.e("Name","name of jsonarray A "+i+" "+name);
                        }

                        JSONArray jsonArrayB=c.getJSONArray("B");
                        for(int k=0;k<jsonArrayB.length();k++){
                            String name=jsonArrayB.getJSONObject(k).getString("name");
                            Log.e("Name","name of jsonarray B "+i+" "+name);
                        }

                    }
                } catch (JSONException e) {
                    e.printStackTrace();
                }
            } else {
                Log.e("ServiceHandler", "Couldn't get any data from the url");
            }

answered Nov 10, 2014 at 6:34

Harsh Parikh

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2 Comments

Ben Over a year ago

Thank you so much for your quick replay. There actually The A B C names I cant put directly into the code because I have received different type of names from reponse.

Harsh Parikh Over a year ago

Put that name in A B C place, and it will do

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