How to extract a substring using regex for this pattern

Question

i have to extract a string between / and ?, i.e exampleproduct

https://local.host.com/order/faces/Home/myorder/exampleproduct?_adf.ctrl-state=mfun9p14r_19

how to write regular expression for this i am using this logic but i am unable to

 private static String extractPageNameFromURL(String urlFull) {    
    if (urlFull != null) {
        Pattern pattern = Pattern.compile("/(.*?).jspx?");
        Matcher matcher = pattern.matcher(urlFull);
        while (matcher.find()) {
            String str1 = matcher.group(1);
            String[] dataRows = str1.split("/");
            urlFull = dataRows[dataRows.length - 1];
        }
    }
    return urlFull;
}


 public static void main(String[] args) {
 System.out.println(DtmUtils.extractPageNameFromURL("https://local.host.com/order/faces/Home/myorder/exampleproduct?_adf.ctrl-state=mfun9p14r_19"));

}

Thanks Raj

stackoverflow.com/questions/27745/getting-parts-of-a-url-regex — Paul Muir
– Paul Muir, Commented Nov 8, 2014 at 15:26

Nathan · Accepted Answer · 2014-11-08 17:01:39Z

If I'm following what you're asking, then you're attempting to pull exampleproduct from the URL.

Here's the regex to use to accomplish this. Group 1 should have the name after the last / and before the first ? after that slash.

^.*\/([^?]+)\?.*$

See an example of the regex

^           -- Beginning of line anchor
.*          -- find 0 or more characters. Note the * is greedy.
\/          -- Find a literal /.
([^?]+)     -- Capture everything that is not a question mark
\?          -- Find a literal question mark
.*          -- now match everything after the question mark
$           -- end of line anchor

and here's a quick example of using it in Java. This is a quick example, and will need to be modified before using it.

String urlFull = "https://local.host.com/order/faces/Home/myorder/exampleproduct?_adf.ctrl-state=mfun9p14r_19";

Pattern pattern = Pattern.compile("^.*\\/([^?]+)\\?.*$");
Matcher matcher = pattern.matcher(urlFull);

matcher.find();

String p = matcher.group(1);
System.out.println(p);

I didn't follow why the original regex you wrote had the .jspx?, but if there's more to the problem you'll need to update the question to explain.

anubhava · Accepted Answer · 2014-11-08 17:06:52Z

0

To match exampleproduct in your input this lookahead based regex will work for you:

[^/]+(?=\?)

In Java code:

Pattern pat = Pattern.compile("[^/]+(?=\\?)");

RegEx Demo

answered Nov 8, 2014 at 17:06

anubhava

790k67 gold badges603 silver badges671 bronze badges

Comments

vatsal · Accepted Answer · 2014-11-08 15:31:24Z

0

This pattern might work for you \?(.*).

This regex finds a question mark and selects everything after it.

answered Nov 8, 2014 at 15:31

vatsal

3,9532 gold badges22 silver badges19 bronze badges

Comments

Leonard · Accepted Answer · 2014-11-08 16:53:14Z

0

I tried this pattern with your path and it worked fine: ([\w_-]*)(\.)*([\w_-]*)?(?=\?)

It would also match, if your filename had a file ending.

edited Nov 8, 2014 at 16:53

answered Nov 8, 2014 at 16:44

Leonard

8345 silver badges23 bronze badges

Collectives™ on Stack Overflow

How to extract a substring using regex for this pattern

4 Answers 4

Comments

RegEx Demo

Comments

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related