When creating an array using numpy, what is the difference between: 1) a = numpy.array((1,2,3)) and 2) a = numpy.array([1,2,3])?
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1 Answer
There is no difference in the output.
a = np.array((1,2,3))
b = np.array([1,2,3])
(a == b).all() # True
The objects that those two commands create are identical.
You can also test equivalence with np.array_equal(a,b), see this question for more info.
Timing
Timing these two expressions has the tuple method with a marginal (insignificant?) advantage, for example in an iPython shell:
In [1]: %timeit a = np.array((1,2,3))
1000000 loops, best of 3: 1.04 µs per loop
In [2]: %timeit a = np.array([1,2,3])
1000000 loops, best of 3: 1.11 µs per loop
Running tests on longer (1 million entries) lists/tuples gives consistently marginal advantage to tuples.
1 Comment
enaJ
Thanks Farenorth! That's very helpful.