How to test if value is in array PHP (key search)

Question

This is my array in PHP:

$arr['key1']='value1';
$arr['key2']='value2';
$arr['key3']='value3';
$arr['key4']='value4';
$arr['key5']='value5';
$arr['key6']='value6';

I would like to test if a key is in the array. Is this function the correct way to proceed?

function isKeyInArray($key, $arr) {
   if(isset($arr[$key]))
      return true;
   else
      return false;
}

What I expect is that:

isKeyInArray('key3', $arr) // return true
isKeyInArray('key9', $arr) // return false

Many thanks in advance.

so whats the problem? correct way to proceed? nothing wrong with this — Kevin
– Kevin, Commented Sep 29, 2014 at 8:28

TeeDeJee · Accepted Answer · 2014-09-29 08:29:49Z

6

You can use array_key_exists.

$a=array("Volvo"=>"XC90","BMW"=>"X5");
if (array_key_exists("Volvo",$a))
  {
  echo "Key exists!";
  }
else
  {
  echo "Key does not exist!";
  }

See http://php.net/manual/en/function.array-key-exists.php

answered Sep 29, 2014 at 8:29

TeeDeJee

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1 Comment

gahse Over a year ago

@UBEX,This code will perform the task as well. But I'll recommend you to use the function you have written yourself as it will give you confidence to write code yourself instead asking here.

Manwal · Accepted Answer · 2014-09-29 08:31:55Z

4

Use array_key_exists

if(array_key_exists('key6',$arr))
   echo "present";
else
   echo "not present";

answered Sep 29, 2014 at 8:31

Manwal

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Comments

olvlvl · Accepted Answer · 2014-09-29 09:02:36Z

2

Using isset() is good if you consider that null is not a suitable value. Also isset is faster than array_key_exists.

$a = [ 'one' => 1, 'two' => null ];
isset($a['one']); // true
isset($a['two']); // false
array_key_exists('two', $a); // true

answered Sep 29, 2014 at 9:02

olvlvl

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Comments

Shemil R · Accepted Answer · 2014-09-29 09:10:38Z

0

Use php function array_key_exists('key3', $a);

First google your need and only after that you can use your own function. This will save lots of your time.

answered Sep 29, 2014 at 9:10

Shemil R

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