Exposing boost::scoped_ptr in boost::python

Question

I am getting a compile error, saying that the copy constructor of the scoped_ptr is private with the following code snippet:

class a {};

struct s
{
  boost::scoped_ptr<a> p;
};

BOOST_PYTHON_MODULE( module )
{
  class_<s>( "s" );
}

This example works with a shared_ptr though. It would be nice, if anyone knows the answer. Thanks

David Rodríguez - dribeas · Accepted Answer · 2010-04-05 08:06:30Z

6

The semantics of boost::scoped_ptr prohibit taking copies, while shared_ptr is intended to be copied. The error you are getting is the compiler telling you that some of the code (macro expansion?) is trying to copy the scoped_ptr but that the library does not allow the copy to be made.

answered Apr 5, 2010 at 8:06

David Rodríguez - dribeas

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