How to retrieve integer value from url of "example_3.html"

Question

Title says it all. Basically I am looking to retrieve the end of the url using jQuery to add one to the selection and go to that page. I had some help from someone else on her but I want to understand how it is working/ why it's not working:

var urlFrags = window.location.href.replace(".html", "").split("_"),

curPage = parseInt(urlFrags[urlFrags.length]),

nextPage = "example_" + (curPage + 1) + ".html";

It could be an error somewhere else, but I am working down the line trying to bug-fix it. I understand pretty much everything going on, except I don't understand parseInt() and stuff.

Would it be possible to '.getAsIntiger(urlFrags)' ? (I have tried this but I may have implemented wrong.)

parseInt() will turn a String into an Integer. If for example you have the string "Text1"*, it will turn into 1. With that 1 you can perform mathematical equetions. *it strips out all the text that cannot be turned into a number. Parameters and more at developer.mozilla.org/de/docs/Web/JavaScript/Reference/… — Spokey
– Spokey, Commented Sep 3, 2014 at 14:59
If your format is same then you could also use replace method to get your desired output as below: "example_" + (parseInt("example_3.html".replace("example_","").replace(".html","")) + 1) + ".html" — D.T.
– D.T., Commented Sep 3, 2014 at 15:05

CodingIntrigue · Accepted Answer · 2014-09-03 14:57:38Z

1

The error there is here:

curPage = parseInt(urlFrags[urlFrags.length]);

You should be doing

curPage = parseInt(urlFrags[urlFrags.length-1]);

Since if you have a length of 2 in your array, you cannot access Array[2] because it doesn't exist. You have to access Array[1] because the array index starts in 0.

edited Sep 3, 2014 at 14:57

CodingIntrigue

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answered Sep 3, 2014 at 14:56

Mindastic

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1 Comment

user2222936 Over a year ago

YOU SIR AND OR MADAM HAVE MADE MY WEEK!

Daiwei · Accepted Answer · 2014-09-03 15:04:26Z

1

Why not do a var num = parseInt(/.+?_(\d+)\.html/.exec(window.location.href)[1])

edited Sep 3, 2014 at 15:04

answered Sep 3, 2014 at 14:59

Daiwei

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1 Comment

CodingIntrigue Over a year ago

Personally I find the OP's solution much easier on the eyes, and I can read Regex just fine. Additionally you are assuming only numbers 0-9 and not double/triple digits.

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