PHP a better way for check non-empty?

Question

The common way for check non-empty var is:

if (!empty($var)) { ... }

Why can't we just use:

if ($var) { ... }

They're the same actually, right?

Ref: http://php.net/manual/types.comparisons.php

error reporting would tell you otherwise

scrowler
– scrowler

2014-09-02 07:22:47 +00:00
Commented Sep 2, 2014 at 7:22 — scrowler
– scrowler, Commented Sep 2, 2014 at 7:22

deceze · Accepted Answer · 2014-09-02 07:35:55Z

7

!empty($var) is exactly the same as just $var, except that with empty no error will be thrown if $var doesn't exist. empty is more or less shorthand for !isset($var) || !$var.

You should never use empty if you expect your variable to exist, because then you're just needlessly suppressing error reporting. Only use empty if you legitimately expect the variable to possibly not exist. This should rarely if ever be the case, if you're initialising your variables properly.

See The Definitive Guide To PHP's isset And empty for an in-depth discussion of this.

edited Sep 2, 2014 at 7:35

answered Sep 2, 2014 at 7:23

deceze♦

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