Creating a simple array

Question

I have the following code:

$page=3;

$i=1;

    while($i<=$pages) {
      $urls .= "'"."http://twitter.com/favorites.xml?page=" . $i ."',";
      $i++;
    }

What I need to create is this array:

$data = array('http://twitter.com/favorites.xml?page=1','http://twitter.com/favorites.xml?page=2','http://twitter.com/favorites.xml?page=3');

How can I produce an array from the while loop?

(reference) de2.php.net/manual/en/language.types.array.php — Gordon
– Gordon, Commented Mar 31, 2010 at 12:18

deceze · Accepted Answer · 2010-03-31 13:06:14Z

6

$urls = array();
for ($x = 1; $x <= 3; $x++) {
    $urls[] = "http://twitter.com/favorites.xml?page=$x";
}

. is for concatenating strings.
[] is for accessing arrays.
[] = pushes a value onto the end of an array (automatically creates a new element in the array and assigns to it).

edited Mar 31, 2010 at 13:06

answered Mar 31, 2010 at 12:19

deceze♦

525k89 gold badges806 silver badges954 bronze badges

Sign up to request clarification or add additional context in comments.

6 Comments

Jonathan Fingland Over a year ago

+1, however it would be better to retain the $pages variable and use that in the for loop condition

Michael D. Irizarry Over a year ago

Ain't it supposed to assign an index to the array $urls[$x] = "twitter.com/favorites.xml?page=$x";

Ben Everard Over a year ago

@Jeremy no, danits example doesn't suggest this, $url[] will auto assign a key.

Jonathan Fingland Over a year ago

@Jeremy, the index is not required, the $urls[] syntax is equivalent to array_push($urls, ....)

Tom Haigh Over a year ago

I think you need $x inside the string , not $i ?

|

codaddict · Accepted Answer · 2010-03-31 12:20:56Z

2

You can do:

$page=3;
$i=1;    
$data = array();
while($i <= $page) {
    $data[] = "http://twitter.com/favorites.xml?page=" . $i++;
}

answered Mar 31, 2010 at 12:20

codaddict

457k83 gold badges501 silver badges537 bronze badges

1 Comment

Ben Everard Over a year ago

Your url value isn't correct, lose the quotes at each end and the comma, he just wants the URL.

Ben Everard · Accepted Answer · 2010-03-31 12:19:42Z

0

Try this instead:

$page=3;

$i=1;
$url=array();

while($i<=$pages) {
    $urls[]="http://twitter.com/favorites.xml?page=".$i ;
    $i++;
}

echo("<pre>".print_r($url,true)."</pre>");

answered Mar 31, 2010 at 12:19

Ben Everard

13.8k14 gold badges69 silver badges96 bronze badges

Collectives™ on Stack Overflow

Creating a simple array

3 Answers 3

6 Comments

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

6 Comments

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related