PHP - Count how many times find a word from array list

Question

first i'm sorry for bad title, my english is not good enough and my little problem is not plain (for me).

Anyway, i have a rudimental script that counts how many times appears a list of words in a string.

$orto1 = substr_count($text," fingger ");
$orto2 = substr_count($text," apears ");
$orto3 = substr_count($text,"ghiven");

$ortog = $orto1 + $orto2 + $orto3;

Now, it's very uncomfortable whenever i've to add a new word, so, i'd like put all words in a array.

So, i've tried with substr_count as well as several examples found here, unsuccessfully.

I'd like to manage to create something like that:

$array = array(" fingger ", " apears ", "ghiven", "suporting");
$total = substr_count($array, $mytext);
echo $total;

Important is case insensitive and "wildcard" matching.

Is it possible or there is another best way?

Thank you at all! Riccardo

Hirnhamster · Accepted Answer · 2014-08-22 14:28:37Z

4

I guess a simple loop will do?

$total = 0
$array = array(" fingger ", " apears ", "ghiven", "suporting");
foreach($array as $word){
  $total += substr_count($word, $mytext);
}
echo $total;

Regarding the case-insensitivity you might use

substr_count(strtoupper($word), strtoupper($mytext))

answered Aug 22, 2014 at 14:28

Hirnhamster

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user3670605 · Accepted Answer · 2014-08-22 14:38:04Z

0

OMG! I had not thought at the simple way like a loop :-)

Anyway, there is a little error:

  $total += substr_count($word, $mytext);

The correct way is:

   $total += substr_count($mytext, $word);

Thank you so much!!!

answered Aug 22, 2014 at 14:38

user3670605

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