what is wrong with this line
Array$j[$i]="10"
when I use this line on my bash script, I got this error: command not found. I think the problem refers to $j. because when I change above to
Array[$i]="10"
I do not get any error. But I need this declaration. because on my bash file. I have to define multiple array with this name
Array1, Array2 , Array3 and ... .
How to chage this line to work correctly:
Array$j[$i]="10"
Ps. j is an loop index. and it give number j=1, j=2, ...
Your problem is not about arrays but variables in general, as you can not do j=foo; $j=bar to get a variable foo with value bar.
You can use eval or declare, at the beginning of the line, to make the substitution before setting the value.
Example:
for i in 1 2 3; do
for j in 1 2; do
eval array$j[$i]=foobar
varname=array$j[$i]
echo ${!varname}
done
done
Use associative arrays if supported (Bash 4.0+):
declare -A Array
Array[$j,$i]=10
echo "${Array[$j,$i]}"
You can use an indirect reference:
$ Array1[0]=10
$ echo "${Array1[0]}"
10
$ j=1
$ arr=Array${j}
$ echo "${!arr[0]}"
10
You can use declare -A to declare the array. This means that the value of $j is expanded before the assignment is made:
$ j=2
$ declare -A array$j="10"
$ echo "${array2[0]}"
10
