java - RegEx replace all but

Question

I've come across a problem with using Regular Expressions in Java. I'm trying to replace everything in a string that doesn't match my expression. Example:

String string = "This is test string (1) of 10";

Basically, I need to remove all the characters in the string to get the value inside the brackets to change it later on. I though that the following would work:

string.replaceAll("^[\\([0-9]\\)]", "(" + nextNumber  +")" );

However, it doesn't. I have also tried:

string.replaceAll("(?!\\([0-9]\\)])", "(" + nextNumber  +")" );

Does anyone know of a better way of getting the value inside the brackets, or could you tell me how I can replace all the characters in the string except the value inside the brackets?

Braj · Accepted Answer · 2014-08-06 19:11:50Z

3

You can try

string.replaceAll("\\([0-9]\\)", "(" + nextNumber  +")" );

There is no need of ^ that represents start of the line.

If the number is more than one digit then try \\([0-9]+\\) and you can use \\d instead of [0-9]

For more info have a look at Java Regex Pattern

answered Aug 6, 2014 at 19:11

Braj

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