Two dates in php script

Question

When I am processing two dates within a php script, the output that is rendered is not what is being expected.

For example when I run

<?php
date_default_timezone_set('EST');
$firstday = date('Y-m-01');
$today = date('Y-m-d');

if ($firstday = $today)
    echo "Today is the 1st <br/>";
else 
    echo "Today is not the 1st <br/>";

echo'The first of the month is: '. $firstday . '<br/>';
echo'Today is: '. $today . '<br/>';
?>

The output is:

Today is the 1st

The first of the month is: 2014-07-30

Today is: 2014-07-30

When it should be

Today is not the 1st.

The first of the month is: 2014-07-01

Today is: 2014-07-30

However when I run one of the date()s at a time, I get that $today = 2014-07-30 and I get $firstdate = 2014-07-01 but not when I run them at the same time.

Can you not run two date() functions at the same time in PHP or do I have it formatted wrong?

Was just going to say that ^^^ you're assigning instead of comparing. Plus, use braces man. — Funk Forty Niner
– Funk Forty Niner, Commented Jul 30, 2014 at 14:04
Wow. Duh. I had that before and I must had accidently deleted it. — user3817073
– user3817073, Commented Jul 30, 2014 at 14:07

tgbrunet · Accepted Answer · 2014-07-30 14:06:01Z

2

Don't assign $today to $firstdate or vice-versa Do $firstday == $today

date_default_timezone_set('EST');
$firstday = date('Y-m-01');
$today = date('Y-m-d');

if ($firstday == $today)
    echo "Today is the 1st";
else 
    echo "Today is not the 1st";

answered Jul 30, 2014 at 14:06

tgbrunet

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