Batch file help using IF with variables

Question

Ok, it's been a little while since I've worked with batch files so I'll admit I'm a little rusty. I'm familiar with getting and input and using it as variable and I know how to use the IF command, just having a little trouble figuring (remembering) the best way to use it. Basically what I want to do is have the user input a number and if that number is one of about 18 different numbers continue to another part of the file and if it is not one of those then continue to a different part.

My question is, do I need to make 18 different IF statements or is there a way to compare all of them with one statement?

What does your script look like so far?

Bill_Stewart
– Bill_Stewart

2014-07-29 16:14:41 +00:00
Commented Jul 29, 2014 at 16:14 — Bill_Stewart
– Bill_Stewart, Commented Jul 29, 2014 at 16:14

Aacini · Accepted Answer · 2014-07-29 17:02:24Z

1

@echo off
setlocal EnableDelayedExpansion

set numberList=2 4 6 8 10 33 212 467
set /P "input=Enter your number: "
if "!numberList:%input%=!" neq "%numberList%" (
   echo Input matches one of the numbers in list
) else (
   echo Input is no one of the list
)

answered Jul 29, 2014 at 17:02

Aacini

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Ir Relevant · Accepted Answer · 2014-07-29 16:21:50Z

0

@echo off

set/p var=What's your choice? 

           set OR=(goto :lable) else if "%var%" ==

if "%var%" == "18" %OR% "296" %OR% "7239" %OR% "whatever" goto :lable
exit/b

:lable
echo worked
pause

answered Jul 29, 2014 at 16:21

Ir Relevant

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Comments

foxidrive · Accepted Answer · 2014-07-29 16:29:53Z

0

Test this:

@echo off
set /p "input=Enter your number: "
set "yes="
for %%a in (2 4 6 8 10 212 33 467) do if "%input%"=="%%a" set yes=1
if defined yes (
   echo input matches
) else ( 
   echo no match
)
pause

answered Jul 29, 2014 at 16:29

foxidrive

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