I have a message that is
msg = 'untagged ethernet 1 ethernet 2 ethernet 3'
and I want to write a regex that will find the 'ethernet x' pattern so that if i run
m = re.match(str(regex),msg)
print m.groups()
it will save the variable x and display something like
(1,2,3)
the expression that I have tried is
regex = 'untagged ((?: ethernet (\S+))*)'
but i am getting
('ethernet 1', 'ethernet 1', '1')\
as a result
You should use re.findall instead of re.match:
>>> import re
>>> msg = 'untagged ethernet 1 ethernet 2 ethernet 3'
>>> re.findall("ethernet\s\d+", msg)
['ethernet 1', 'ethernet 2', 'ethernet 3']
>>> re.findall("ethernet\s(\d+)", msg) # Just the numbers
['1', '2', '3']
>>> tuple(map(int, re.findall("ethernet\s(\d+)", msg))) # What was in your post
(1, 2, 3)
>>>
re.findall was designed explicitly for finding all occurrences of a pattern inside a string.