PHP: Get instance of static class by string value

Question

I'm working on a php web api that was handed to me with a lot of code that needs to be refactored. The ones that wrote the code wanted to include a static configuration class to an api resource and then get an instance of that class something like this:

<?php
$obj = "User";
$confObjectSuffix = "_conf";
$confObject = $obj.$confObjectSuffix;
if ($confObject::inst()->checkMethod($method)) {
.....

This gives the error "Parse error: syntax error, unexpected T_PAAMAYIM_NEKUDOTAYIM in ....." since $confObject is a string and not a object.

I wrote some testcode:

<?php

$class = "User_conf";
echo "<pre>";
print_r($$class::Inst());
echo "</pre>";

class User_conf {
    private static $INSTANCE = null;

    public static function Inst() {
        if(User_conf::$INSTANCE === null) {
            User_conf::$INSTANCE = new User_conf();
        }

        return User_conf::$INSTANCE;
    }
}

But can't get it to work with $$ either, is there some other way around this? I don't want to rewrite more than necessary.

Tatu Ulmanen · Accepted Answer · 2010-03-22 11:26:57Z

6

You can use call_user_func to capture the instance, then process it as needed:

$instance = call_user_func(array($confObject, 'inst'));

if($instance->checkMethod($method)) {
    ...

answered Mar 22, 2010 at 11:26

Tatu Ulmanen

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