Javascript Object constructor as a method of another object

Question

I have this object:

var x = function(){

    var returnObj = {

        constructor:function(ieps){

            this.jow = ieps

        }

    }

    returnObj.constructor.prototype.build = function(){

        alert(this.jow)

    }

    return returnObj

}

That i would like to call with this:

var jow = new x.constructor("ieps")
jow.build()

So i try to get the build() to execute the alert but i get a x.build() is undefined.

Any ideas?

thx,

I guess you want to call x: new (x().constructor)('foo'). You can only access the return value of the function if you call the function. — Felix Kling
– Felix Kling, Commented Jul 22, 2014 at 14:54
You're trying to use a module pattern, but neglected to invoke the outer function. Just add () to the end of that function. — cookie monster
– cookie monster, Commented Jul 22, 2014 at 15:06
Notice that you probably shouldn't create constructors inside a function (except that function is supposed to be used as a singleton). — Bergi
– Bergi, Commented Jul 22, 2014 at 15:07

Nikola Dimitroff · Accepted Answer · 2014-07-22 14:56:48Z

1

x is a function that returns the object, which has a constructor as property. You must first call the function. Secondly, you can't go with new x().constructor("ieps") since that gets parsed as (new x()).constructor("ieps") but you actually need new (x().constructor)("ieps"). Finally, we arrive at:

var jow = new (x().constructor)("ieps")
jow.build()

answered Jul 22, 2014 at 14:56

Nikola Dimitroff

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1 Comment

kevinius Over a year ago

var jow = new x().constructor("ieps") was actually enough (so no extra explicit expression forcing needed, the extra ()

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