Get array through an jQuery AJAX call doesn't work

Question

I have the following code:

 var data = $(this).sortable('serialize');
$.ajax({
                    data: {order: data, actionFor: 'main_articles'},
                    type: 'POST',
                    url: 'updateDisplayOrder.php',
                    success: function (msg) { //re-number the rows from 1 to n
                       //code goes here
                    },
                    error: function () {
                        alert("An error occurred");
                    });

And the PHP:

    require_once('../lib/common/db_connect.php');
    $ids = array();
    $actionFor = $_POST['actionFor'];
    foreach ($_POST['order'] as $value) //error here {
    //more code goes here
    }

The problem is that I get this error on the foreach line:

Warning: Invalid argument supplied for foreach()

I noticed that if I change this line:

 data: {order: data, actionFor: 'main_articles'},

To

data:data

And in the PHP :

foreach ($_POST['order'] as $value) //error here {

To

foreach ($_POST['item'] as $value)

It Works great. Why? How can I fox it? thanks!

Your POST parameter will be a string; if that string is actually JSON, you need to parse it to be an array before trying to iterate through it using foreach. — Anthony Grist
– Anthony Grist, Commented Jul 14, 2014 at 15:22
@Styphon I got this: 'string(35) "item[]=2&item[]=1&item[]=3&item[]=4"' — Nave Tseva
– Nave Tseva, Commented Jul 14, 2014 at 15:34
@NaveTseva We'll there's your answer. It's not an array, it's a string. As Anthony Grist said, you need to parse it into an array first. — Styphon
– Styphon, Commented Jul 14, 2014 at 15:38
@Styphon Yes I noticed it now, can you take a look again at the question? I updated it and it seems strange to me that it's a string — Nave Tseva
– Nave Tseva, Commented Jul 14, 2014 at 15:40

Styphon · Accepted Answer · 2014-07-14 15:44:01Z

1

$_POST['order'] contains a string, not an array. You need to parse your string into an array first. Try this:

$order = array();
$stg1 = explode("&", $_POST['order']);
$i = 0;
foreach($stg1 as $keyval) {
    list($key, $val) = explode("=", $keyval);
    $order[$i++] = $val;
}

Then you can do your foreach($order as $value) as you wish.

answered Jul 14, 2014 at 15:44

Styphon

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