CREATE TABLE Posts
{
id INT PRIMARY KEY AUTO_INCREMENT,
title VARCHAR(200),
url VARCHAR(200)
}
json.php code
<?php
$sql=mysql_query("select * from Posts limit 20");
echo '{"posts": [';
while($row=mysql_fetch_array($sql))
{
$title=$row['title'];
$url=$row['url'];
echo '
{
"title":"'.$title.'",
"url":"'.$url.'"
},';
}
echo ']}';
?>
I have to generate results.json file.
To generate JSON in PHP, you need only one function, json_encode().
When working with database, you need to get all the rows into array first. Here is a sample code for mysqli
$sql="select * from Posts limit 20";
$result = $db->query($sql);
$posts = $result->fetch_all(MYSQLI_ASSOC);
then you can either use this array directly or make it part of another array:
echo json_encode($posts);
// or
$response = json_encode([
'posts' => $posts,
]);
if you need to save it in a file then just use file_put_contents()
file_put_contents('myfile.json', json_encode($posts));
fwrite($fp, json_encode($response,JSON_PRETTY_PRINT)); - uses whitespace to format the JSON. Other constants hereUse this:
$json_data = json_encode($posts);
file_put_contents('myfile.json', $json_data);
You can create the myfile.json before you run the script.But its not compulsory if you have full sudo privileges(read/write permissions(For of you on Mac).
Here is a working Example:
<?php
// data stored in an array called posts
$posts = Array (
"0" => Array (
"id" => "01",
"title" => "Hello",
),
"1" => Array (
"id" => "02",
"title" => "Yoyo",
),
"2" => Array (
"id" => "03",
"title" => "I like Apples",
)
);
// encode array to json
$json = json_encode($posts);
$bytes = file_put_contents("myfile.json", $json); //generate json file
echo "Here is the myfile data $bytes.";
?>
Example2: Another example with a json data and error handling.
<?php
// Data stored in an array called posts
$posts = [
[
"id" => "01",
"title" => "Hello",
],
[
"id" => "02",
"title" => "Yoyo",
],
[
"id" => "03",
"title" => "I like Apples",
]
];
// Encode array to JSON with formatting
$json = json_encode($posts, JSON_PRETTY_PRINT);
// Write JSON to file and handle errors
$file = "myfile.json";
if (file_put_contents($file, $json) !== false) {
echo "Data has been written to $file.";
} else {
echo "Error occurred while writing to $file.";
}
?>
When JSON_PRETTY_PRINT is passed as the second argument to json_encode(), it tells the function to add whitespace and formatting to the generated JSON string. This makes the resulting JSON structure easier to read and understand when viewing it directly.
Example3: With SQL data from a server:
<?php
// Connect to the database
$servername = "localhost";
$username = "your_username";
$password = "your_password";
$dbname = "your_database";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
// Fetch data from the database
$sql = "SELECT id, name, email FROM users";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
$users = array();
while ($row = $result->fetch_assoc()) {
$users[] = $row;
}
// Encode SQL data to JSON
$json = json_encode($users, JSON_PRETTY_PRINT);
// Write JSON to file
$file = "users.json";
if (file_put_contents($file, $json) !== false) {
echo "Data has been written to $file.";
} else {
echo "Error occurred while writing to $file.";
}
} else {
echo "No data found.";
}
// Close the database connection
$conn->close();
?>
file_put_contents works that I mentioned in my initial comment.Insert your fetched values into an array instead of echoing.
Use file_put_contents() and insert json_encode($rows) into that file, if $rows is your data.
If you're pulling dynamic records it's better to have 1 php file that creates a json representation and not create a file each time.
my_json.php
$array = array(
'title' => $title,
'url' => $url
);
echo json_encode($array);
Then in your script set the path to the file my_json.php
Here i have mentioned the simple syntex for create json file and print the array value inside the json file in pretty manner.
$array = array('name' => $name,'id' => $id,'url' => $url);
$fp = fopen('results.json', 'w');
fwrite($fp, json_encode($array, JSON_PRETTY_PRINT)); // here it will print the array pretty
fclose($fp);
Hope it will works for you....
First, you need to decode it :
$jsonString = file_get_contents('jsonFile.json');
$data = json_decode($jsonString, true);
Then change the data :
$data[0]['activity_name'] = "TENNIS";
// or if you want to change all entries with activity_code "1"
foreach ($data as $key => $entry) {
if ($entry['activity_code'] == '1') {
$data[$key]['activity_name'] = "TENNIS";
}
}
Then re-encode it and save it back in the file:
$newJsonString = json_encode($data);
file_put_contents('jsonFile.json', $newJsonString);
You can simply use json_encode function of php and save file with file handling functions such as fopen and fwrite.
