Php button action event needed

Question

How do i implement button click php when either one of the buttons is clicked? I am trying to do is, if sumbit button is clicked the php script below shows it written to a file and if view comments is hit shows comments

 <html> 
<body>

  <form action="http://localhost/class/assignment10.php" method="post">
  User Name: <input type="text" name="uname"><br>
  User Comments: <textarea type ="text" name="tcomment"></textarea><br>
  <input type="submit" value="Submit Comments"/> 
  <input type="submit" value="View Comments"/>


  </form>

  </body>
  </html>

I have two form buttons IF submit comments is clickedthe php code should write the user’s name and comments to a text file (use fputs function to write to a file. Also you should insert a newline after each name and each comment). When user’s name and comments are successfully recorded, php should direct

On the other hand, if a user clicks on the ‘view all comments’ button, the php code should show all users and their corresponding comments (use fgets function)

 <html>
 <head>
 <title>PHPLesson10</title>
 </head>

 <body>

 <?php
  // Collect user name and add a line break at the end.
  $customer = $_POST['uname']."\n";
  // Collect comment and add a line break.
  $comments = $_POST['tcomment']."\n";

  $file = fopen("C:/data/feedback.txt", "a");
  If ($file) // if the file open successfully
  {
    // Write the variables to the file.
  fputs($file, $customer);
  fputs($file, $comments);
  fclose($file);
   }
   Else
   {
    Echo "Please try again.";
  }
  ?>

  </body>
  </html>


   <?php
  // Open the file feedback for reading
 $file = fopen("C:/data/feedback.txt", "r");
 // While the end of the file has NOT reached
 While (!feof($file))
 {
  // Print one line of file
 Echo fgets($file);
 Echo "<br />";
}
// close the connection
fclose($file);
?>

PHP executes server side. You're going to have to look into JavaScrpt and Ajax. And even then, I'm not so sure you will be able to write to the user's machine. — durbnpoisn
– durbnpoisn, Commented Jul 1, 2014 at 15:14

Suman Biswas · Accepted Answer · 2014-07-01 15:17:21Z

1

Your submit buttons should like below :

<input type="submit" name="submit_comment" value="Submit Comments"/> 
<input type="submit" name="view_comment" value="View Comments"/>

And your php code for each buttons should like below:

<?php
    if(isset($_POST['submit_comment']))
    {
        //the php  code will be here for save comment
    }
    if(isset($_POST['view_comment']))
    {
       //the php code will be here for view comment
    }

?>

answered Jul 1, 2014 at 15:17

Suman Biswas

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Comments

Nebojsa Susic · Accepted Answer · 2014-07-01 15:25:23Z

1

use name attribute on buttons

<input type="submit" value="Submit Comments" name="btn_submit"/>
<input type="submit" value="View Comments" name="btn_view"/>

then on php you can check something like

if (isset($_POST['btn_submit']))...

or

if (isset($_POST['btn_view']))...

Best regards, Nebojsa

answered Jul 1, 2014 at 15:25

Nebojsa Susic

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Comments

Andy Castille · Accepted Answer · 2014-07-01 15:26:08Z

For buttons, I usually use <button> tags and not <input> tags, as long as you're using <!doctype html> for HTML5.

<form action="http://localhost/class/assignment10.php" method="post" id="commentForm">
    <button type="submit" name="action" value="submit" form="commentForm">
        Submit Comments
    </button>
    <button type="submit" name="action" value="view" form="commentForm">
        View Comments
    </button>
</form>

Then use PHP to figure out what the user clicked like this:

<?php

    $action = $_POST["action"];

    if ($action == "submit") {
        // submission code
    }

    if ($action == "view") {
        // viewing code
    }

    else {
        die("Your request could not be completed.");
    }

?>

Reece Kenney · Accepted Answer · 2014-07-01 16:01:48Z

-1

First give your submit buttons a name like so:

<input type="submit" name="button1" value="Submit Comments"/>
<input type="submit" name="button2" value="View Comments"/>

and then use this PHP:

<?php
    if (isset(@$_POST['button1'])) {
       //Code to execute
    }
    if (isset(@$_POST['button2'])) {
        //Code to execute
    }
?>

edited Jul 1, 2014 at 16:01

answered Jul 1, 2014 at 15:17

Reece Kenney

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