PHP generate JSON code [duplicate]

Question

Model JSON: https://dl.dropboxusercontent.com/s/vjq9j5gwkbrly3y/data.json

How can I generate the above JSON using PHP, including the separate categories in to the above model?

I need help to separate the above categories for JSON. Do I have to do several selects?

Not sure what you mean by do i have to do several selects....as you're not mentioning MYSQL at all , youre asking how to generate JSON with php — Kylie
– Kylie, Commented Jun 27, 2014 at 22:01

Kylie · Accepted Answer · 2014-06-27 22:00:08Z

2

Just build your arrays,

    $array = array("Restaurants"=>array(
      array("ID"=>23,"name"=>"test","example"=>"ex"),
      array("ID"=>23,"name"=>"test","example"=>"ex"),
      array("ID"=>23,"name"=>"test","example"=>"ex")
     ),
    "Categories"=>array(
      array("cat"=>"example","ex"=>"example"),
      array("cat"=>"example","ex"=>"example")
     )
     );

Then use json_encode

    echo json_encode($array);

EXAMPLE

edited Jun 27, 2014 at 22:00

answered Jun 27, 2014 at 21:54

Kylie

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