Passed array to php from jquery with ajax value just shows Array not actual array value

Question

Please can someone tell me where I'm going wrong js file:

//Checkboxid is an array which is populated using .push();
$.ajax({
    type: "POST",
    url: "test.php",
    dataType: 'html',
    data: { data: Checkboxid },
    success: function (data) {
        console.log(data);

    }
});

test.php:

<?php
 $test = $_POST['data'];
 for ($i = 0; $i < count($test); ++$i) {
        echo $test[$i];
    }

    foreach($test as $val) {
    echo $val;
}
?>

console.log displays:

ArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArrayArray

array(26) { [0]=> array(1) { [0]=> string(28) "Adverse_Weather_Conditionsv1" } [1]=> array(1) { [0]=> string(21) "Bank_Holiday_Policyv1" } — user3493928
– user3493928, Commented Jun 25, 2014 at 10:42
If I do for (var i = 0; i < Checkboxid.length ; i++) { console.log(Checkboxid[i]); } just before the ajax it displays fine. — user3493928
– user3493928, Commented Jun 25, 2014 at 10:45
what is the result of console.log(checkboxid) in javascript? — nicowernli
– nicowernli, Commented Jun 25, 2014 at 10:46

Think Different · Accepted Answer · 2014-06-25 10:46:05Z

1

Your $test variable is a two-dimensional array. Try this

<?php
   $test = $_POST['data'];

  foreach($test as $arr) {
     foreach($arr as $val){
          echo $val;
     }
  }
?>

answered Jun 25, 2014 at 10:46

Think Different

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2 Comments

user3493928 Over a year ago

Haha Thank you so much I started coding this last night came back to it this morning I completely forgot it was 2D. I thought I was going insane.

Enjoyted Over a year ago

You should always think about dimensional arrays when your print tests are "Array" :)

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