In Ruby i do so
asd = 123
asd = '%b' % asd # => "1111011"
-
Duplicate: stackoverflow.com/questions/1993834/…S.Lott– S.Lott2010-03-12 18:41:32 +00:00Commented Mar 12, 2010 at 18:41
-
The "duplicate" is for Python 2.5. Languages constantly evolve, don't be too eager to post "duplicate" question links.Humphrey Bogart– Humphrey Bogart2010-03-12 21:33:16 +00:00Commented Mar 12, 2010 at 21:33
Add a comment
|
3 Answers
you can also do string formatting, which doesn't contain '0b':
>>> '{:b}'.format(123) #{0:b} in python 2.6
'1111011'
4 Comments
Felix Kling
Olivier Verdier
Pretty cool! But it should be
'{0:b}'.format(123), and it is for python version ≥ 2.6 only.
edtsech
Great, it is that i find out.
SilentGhost
@Oliver: comment says it.
'{:b}' is python 2.7 and 3.1 version.in Python >= 2.6 with bin():
asd = bin(123) # => '0b1111011'
To remove the leading 0b you can just take the substring bin(123)[2:].
bin(x)
Convert an integer number to a binary string. The result is a valid Python expression. Ifxis not a Python int object, it has to define an__index__()method that returns an integer.New in version 2.6.
3 Comments
Justin Peel
You could also remove the leading '0b' by doing bin(123).strip('0b').
tgray
@Justin, you should use
lstrip instead of strip as the latter will strip any 0s from the end of the string as well as the front (thereby changing the value). The slice is probably a better way to go, as it will only ever remove those two characters from the string.Justin Peel
@tgray Yes, I agree now that I have thought about it a little more.
bin() works, as Felix mentioned. For completeness, you can go the other way as well.
>>> int('01101100',2)
108
>>> bin(108)
'0b1101100'
>>> bin(108)[2:]
'1101100'
