How can I make an array of object in my function parameter call a function for each object?

Question

I created the following checkGrid function which takes a count and then another two parameters. It's a solution which hardcodes in the selectOption calls and is not very flexible:

checkGrid = function(expectCount, typeParam, selectParam) {

   it('Check', function () {
      selectOption('examTypeSelect', typeParam).click();
      selectOption('examStatusSelect', selectParam).click();
    });

}
checkGrid(10, '*', '*');

Now I would like to make this more flexible so that it accepts arguments for any number of selectOption functions. So I was thinking of something that I could call like this. HEre what I would need is for the checkGrid function to call the selectOption three times:

checkGrid(10, [{'examTypeSelect','*'}
               {'examStatusSelect', '*'},
               {'abcSelect','29'}]);

How could I take an array object that's the second parameter for checkGrid and make it so that it calls any number of selectOption functions depending on how many elements there are in the array?

Naturally, you'd receive the Array as an argument, and use a for loop. — cookie monster
– cookie monster, Commented Jun 15, 2014 at 16:23
...but your object syntax is invalid. Eloquent JavaScript, Chapter 4, Data structures: Objects and Arrays Though based on this question, you already know proper object initializer syntax, so I'm not sure why you're not using it in this question. — cookie monster
– cookie monster, Commented Jun 15, 2014 at 16:24

Jon · Accepted Answer · 2014-06-15 16:33:53Z

2

By using a loop over the array and .apply to call each function with a variable number of arguments.

checkGrid = function(expectCount, stuff) {
    it('Check', function () {
        for (var i = 0; i < stuff.length; ++i) {
            selectOption.apply(this, stuff[i]).click();
        }
    });
}

You would call this not with your proposed syntax (which is invalid), but like

checkGrid(10, [
                ['examTypeSelect','*'],
                ['examStatusSelect', '*'],
                ['abcSelect','29','and','perhaps','more','parameters']
              ]
          );

Finally, it's unclear what expectCount is supposed to do but I left it there because your original code presumably does something with it.

edited Jun 15, 2014 at 16:33

answered Jun 15, 2014 at 16:27

Jon

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6 Comments

Jon Over a year ago

@cookiemonster: I wouldn't change the value of this inside the body of selectOption.

Samantha J T Star Over a year ago

thanks. I did not know about the need for an apply. As far as the syntax in my call goes. Is that syntax correct as a way to call the function. Yes you are correct about expectCount. That's needed but I didn't include that code so I could make it a simpler question. Thanks

cookie monster Over a year ago

Yeah, I was wrong, though the proper this would actually be the default since the original code doesn't pass the enclosed this.

Jon Over a year ago

@SamanthaJ: {'examTypeSelect','*'} etc is incorrect syntax, period.

cookie monster Over a year ago

@SamanthaJ: You should be aware that you don't really need .apply() here to do what you want, as long as you know each call will have 2 arguments. selectOption(stuff[0], stuff[1]);. Also, you don't need an Array of Arrays (or Objects). You can pass as many objects as you want to checkGrid, and then loop the arguments object starting at index 1. This way you're using checkGrid as a variadic function, meaning the number of arguments it receives is determined when invoked.

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