php - Unexpected behavior when assigning a variable with new

Question

I am a bit confused with the following code example. I would guess that the second assignment $ins = new A(); would override the previous $ins reference.

I also don't understand the #1, #2, neither the (1),(1) in the var_dump output, I would expect at least (0),(0).

Thanks in advance

class A{

    public $var = 2;

}

$ins = new A();

$aux = &$ins;

$ins->var = 3;

var_dump($aux);
echo '<br>';

$ins = new A();

$ins->var = 5;

var_dump($aux);

prints

object(A)#1 (1) { ["var"]=> int(3) }
object(A)#2 (1) { ["var"]=> int(5) }

the 1's represent how many values it sees as a count of values in the array. — VikingBlooded
– VikingBlooded, Commented Jun 11, 2014 at 20:28
Thanks, I found an answer there php.net//manual/en/language.oop5.references.php#95522 — Pablo Riera
– Pablo Riera, Commented Jun 11, 2014 at 20:33

FuzzyTree · Accepted Answer · 2014-06-11 20:31:30Z

1

http://www.php.net//manual/en/language.oop5.references.php

A PHP reference is an alias, which allows two different variables to write to the same value. As of PHP 5, an object variable doesn't contain the object itself as value anymore. It only contains an object identifier which allows object accessors to find the actual object. When an object is sent by argument, returned or assigned to another variable, the different variables are not aliases: they hold a copy of the identifier, which points to the same object.

answered Jun 11, 2014 at 20:31

FuzzyTree

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