Looping variable variables, illegal string offset

Question

I keep getting

Warning: Illegal string offset 'type' in ... on line ...

I've tried following the answers here Illegal string offset Warning PHP

by doing something like

if(isset($_POST['type_'.$i]))
     $$T['type'] = $_POST['type_'.$i];

but it still gives errors, I think it might have something to do with variable variables (it's the first time I am using them. Below is my code:

for($i = 1; $i <= 15; $i++){
    $T = 'T'.$i;

    $$T['type'] = $_POST['type_'.$i];
    $$T['hidden'] = $_POST['hidden_'.$i];
    $$T['require'] = $_POST['require_'.$i];
    if(isset($_POST['question_'.$i.'_list']))
        $$T['list'] = $_POST['quesiton_'.$i.'_list'];
}

I won't like to create arrays T1, T2 ... T15, with the following values ['type'], ['hidden'], ['require'], ['list'].

Try adding $$T = array(); before trying to assign any values to it. — Styphon
– Styphon, Commented Jun 10, 2014 at 22:16
so you want each of your T variables to be arrays? What if you set them to be before setting the values inside them? $$T = array(); — didierc
– didierc, Commented Jun 10, 2014 at 22:16
Either the variable $T is not an array and you are trying to access it like it is or you need to wrap $T['type'] in curly braces because the $$T assignment is happening before the array lookup. Try ${$T['type']}. Curly braces in assignment are like parenthesis in expressions. $$T is likely doing a string conversion of the array $T making a variable called $Array and then looking up a key of ['type'] on the string. — Jonathan Kuhn
– Jonathan Kuhn, Commented Jun 10, 2014 at 22:17

didierc · Accepted Answer · 2014-06-10 22:26:40Z

3

How's that?

for($i = 1; $i <= 15; $i++){
    $T = 'T'.$i;
    $$T = array(
      'type' => $_POST['type_'.$i], 
      'hidden' => $_POST['hidden_'.$i],
      'require' => $_POST['require_'.$i]);

    if(isset($_POST['question_'.$i.'_list']))
        ${$T}['list'] = $_POST['question_'.$i.'_list'];
}

edited Jun 10, 2014 at 22:26

answered Jun 10, 2014 at 22:19

didierc

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Niet the Dark Absol · Accepted Answer · 2014-06-10 22:19:13Z

2

The problem is one of precedence. $T['type'] is resolved first, and then used as the variable name for $___.

Since $T is a string, ['type'] is an invalid offset to get.

You could do this:

${$T}['type']

... I think. I wouldn't really know, because stuff like this is what arrays were kinda made for ;)

$T = array();
for( $i = 1; $i <= 15; $i++) {
    $row = array(
        "type" => $_POST['type_'.$i],
        "hidden" => $_POST['hidden_'.$i],
        "require" => $_POST['require_'.$i]
    );
    if( isset($_POST['question_'.$i.'_list'])) {
        $row['question_'.$i.'_list'] = $_POST['question_'.$i.'_list'];
    }
    $T[] = $row;
}

answered Jun 10, 2014 at 22:19

Niet the Dark Absol

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