Parse JsonArray without key in android

Question

i have a json response but is this standard format?

[{"code":"123","rate":"0.1","title":"sss","subtitle":"mmm"},{"code":"456","rate":"0.1","title":"bbb","subtitle":"uuu"}]

and how can i pars it in android?

new JSONObject(result.toString())

throw below exception!

06-07 11:45:54.943: W/System.err(10310):    at org.json.JSON.typeMismatch(JSON.java:111)
06-07 11:45:54.943: W/System.err(10310):    at org.json.JSONObject.<init>(JSONObject.java:158)
06-07 11:45:54.943: W/System.err(10310):    at org.json.JSONObject.<init>(JSONObject.java:171)

yes it's valid you can paste your Json in jsonlint.com for check validation — Shayan Pourvatan
– Shayan Pourvatan, Commented Jun 7, 2014 at 7:27
your json is an Array not an object so you need new JSONArray(result.toString()); — Shayan Pourvatan
– Shayan Pourvatan, Commented Jun 7, 2014 at 7:28

T.J. Crowder · Accepted Answer · 2014-06-07 07:25:41Z

3

i have a json response but is this standard format?

It would be without the < at the beginning and the > at the end. So:

new JSONObject(result.toString().substring(1, result.length() - 2));

or more likely:

new JSONArray(result.toString().substring(1, result.length() - 2));

~~since the top level of it is an array.~~

Since you've removed the < and > you had originally:

Since the top level of it is an array, you probably want JSONArray, not JSONObject:

new JSONArray(result.toString());

answered Jun 7, 2014 at 7:25

T.J. Crowder

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4 Comments

M.Movaffagh Over a year ago

you are correct.but the problem is not < and >;thanks

T.J. Crowder Over a year ago

@Mimad: In what way is not those? Those make it invalid JSON, so you can't parse it. Without them, it is valid JSON, and you can parse it. (Also: You probably want new JSONArray rather than new JSONObject, as it's an array, not an object. I've added that.)

M.Movaffagh Over a year ago

it s my fault in logging!:D

T.J. Crowder Over a year ago

@Mimad: Ah, okay. So it's just the JSONObject vs. JSONArray thing.

MilapTank · Accepted Answer · 2014-06-07 07:28:12Z

3

this is JSONarray

[{"code":"123","rate":"0.1","title":"sss","subtitle":"mmm"},{"code":"456","rate":"0.1","title":"bbb","subtitle":"uuu"}]

try to parse

 new JSONArray(result.toString())

answered Jun 7, 2014 at 7:28

MilapTank

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Comments

VairavelRajendran · Accepted Answer · 2014-06-07 07:36:55Z

1

First assign your json array like this

JSONArray jsar=new JSONArray(result);

then parse objects like this

for(int i=0;i<jsar.length;i++)
{
JSONObject jsobj=new JSONObject(jsar[i]);

String strcode=jsobj.get("code");

String strrate=jsobj.get("rate");

String strtitle=jsobj.get("title");

String strsubtitle=jsobj.get("subtitle");
}

hope this will help you,.

answered Jun 7, 2014 at 7:36

VairavelRajendran

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