Submit form with multiple input with the same name

Question

I would like to be able to send multiple dropdown values with the same name to insert them in the database

can somebody help me??

<?php
session_start();
require_once('Connections/koneksi.php');

if($_REQUEST['submit'] == "Submit")
{   
    $name       = $_POST["user"];       
    $masukdatabase = "INSERT INTO `com`(`user`) Values('$ame')";        
}
?>

<html>
<head>
<script>
function addRow(tableID) {
    var table = document.getElementById(tableID);
    var rowCount = table.rows.length;
    var row = table.insertRow(rowCount);
    var colCount = table.rows[0].cells.length;
    for(var i=0; i<colCount; i++) {
        var newcell = row.insertCell(i);
        newcell.innerHTML = table.rows[0].cells[i].innerHTML;

        switch(newcell.childNodes[0].type) {
                    case "text":
                            newcell.childNodes[0].value = "";
                            break;
                    case "checkbox":
                            newcell.childNodes[0].checked = false;
                            break;
                    case "select-one":
                            newcell.childNodes[0].selectedIndex = 0;
                            break;
                }

    }
}
function deleteRow(tableID) {
    try {
    var table = document.getElementById(tableID);
    var rowCount = table.rows.length;
    for(var i=0; i<rowCount; i++) {
        var row = table.rows[i];
        var chkbox = row.cells[0].childNodes[0];
        if(null != chkbox && true == chkbox.checked) {
            if(rowCount <= 1) {
                alert("Cant delete all rows");
                break;
            }
            table.deleteRow(i);
            rowCount--;
            i--;
        }
    }
    }catch(e) {
        alert(e);
    }
}


</script>

</head>
<body>
<form name="form1" method="post" action="adduser.php">                                 
    <table id="dataTable" width="auto" style="margin:-4px 0 0 0;" cellspacing="0px">
    <tr>
    <td style="width:20px;"><INPUT type="checkbox" name="chk" /></td>
    <td><select name="user" id="user">
    <option value="tono">tono</option>
    <option value="tini">tini</option>
    </select></td>                           
    </tr>
    </table>
<INPUT type="button" value="Add row" onclick="addRow('dataTable')" />
<INPUT type="button" value="Delete row" onclick="deleteRow('dataTable')" />                 


</form>

</body>
</html>

Can you explain a little bit more? do you want to add what value on what dropdown list? the new one? — SERPRO
– SERPRO, Commented Jun 3, 2014 at 10:28
i want add value from dropdown menu <select name="user" id="user"> <option value="tono">tono</option> <option value="tini">tini</option> </select> to database. i use addrow function, i just can get the first row from dropdown value but i can't get value from the second and other row — Ferdinand
– Ferdinand, Commented Jun 4, 2014 at 2:19
halooo... is there anyone can help me to solve this... thank you — Ferdinand
– Ferdinand, Commented Jun 4, 2014 at 8:46

SERPRO · Accepted Answer · 2014-06-04 09:17:03Z

What you need to do to send more than 1 select with the same name is make it an array by adding [] and the end of its name name="user" becomes name="user[]". Then when you receive the variable via POST it will be an array

Using your example:

adduser.php

<?php
if($_SERVER['REQUEST_METHOD'] === 'POST')
{   
    foreach($_POST['user'] as $name)
    {
        $masukdatabase = "INSERT INTO `com`(`user`) Values('${name}')";
    }
}
?>

index.html

<html>
<head>
<script>
function addRow(tableID) {
    var table = document.getElementById(tableID);
    var rowCount = table.rows.length;
    var row = table.insertRow(rowCount);
    var colCount = table.rows[0].cells.length;
    for(var i=0; i<colCount; i++) {
        var newcell = row.insertCell(i);
        newcell.innerHTML = table.rows[0].cells[i].innerHTML;

        switch(newcell.childNodes[0].type) {
                    case "text":
                            newcell.childNodes[0].value = "";
                            break;
                    case "checkbox":
                            newcell.childNodes[0].checked = false;
                            break;
                    case "select-one":
                            newcell.childNodes[0].selectedIndex = 0;
                            break;
                }

    }
}
function deleteRow(tableID) {
    try {
    var table = document.getElementById(tableID);
    var rowCount = table.rows.length;
    for(var i=0; i<rowCount; i++) {
        var row = table.rows[i];
        var chkbox = row.cells[0].childNodes[0];
        if(null != chkbox && true == chkbox.checked) {
            if(rowCount <= 1) {
                alert("Cant delete all rows");
                break;
            }
            table.deleteRow(i);
            rowCount--;
            i--;
        }
    }
    }catch(e) {
        alert(e);
    }
}


</script>

</head>
<body>
<form name="form1" method="post" action="adduser.php">                                 
    <table id="dataTable" width="auto" style="margin:-4px 0 0 0;" cellspacing="0px">
    <tr>
    <td style="width:20px;"><INPUT type="checkbox" name="chk" /></td>
    <td><select name="user[]" id="user">
    <option value="tono">tono</option>
    <option value="tini">tini</option>
    </select></td>                           
    </tr>
    </table>
<INPUT type="button" value="Add row" onclick="addRow('dataTable')" />
<INPUT type="button" value="Delete row" onclick="deleteRow('dataTable')" />                 
<input type="submit" value="Submit" />
</form>

</body>
</html>

IT WORKS!!!! yessss.... many thankss SERPRO... i was suprised if it just need adding a simple code.... thank you so much...

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