Java String.indexOf API

Question

I have following situation,

String a="<em>crawler</em> <em> Yeahhhhh </em></a></h3><table";
System.out.println(a.indexOf("</em>"));

It returns the 11 as the result which was the first that it founds.

Is there any way to detect the last instead of the first one for the code written above?

Adriaan Stander · Accepted Answer · 2010-03-06 06:40:37Z

5

Have a look at indexOf( ) and lastIndexOf( ) in Java

and

lastIndexOf

answered Mar 6, 2010 at 6:40

Adriaan Stander

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1 Comment

Mr CooL Over a year ago

Thanks man....I thought the lastIndexOf returns the last index of the same occurrence...overlooked that part...Thanks...

polygenelubricants · Accepted Answer · 2010-03-06 07:08:31Z

1

lastIndexOf gives you the index of the last occurrence of needle in the haystack, but the following example of finding all occurrences may also be instructive:

for (int pos = -1; (pos = haystack.indexOf(needle, pos + 1)) != -1;) {
    System.out.println(pos);
}

To find all occurrences backward, you do the following:

for (int pos = haystack.length(); (pos = haystack.lastIndexOf(needle, pos - 1)) != -1;) {
    System.out.println(pos);
}

edited Mar 6, 2010 at 7:08

answered Mar 6, 2010 at 7:02

polygenelubricants

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