If you have a list in python, and you want the elements from 2 to n can do something nice like
list[2:]
I'd like to something similar with argv in Bash. I want to pass all the elements from $2 to argc to a command. I currently have
command $2 $3 $4 $5 $6 $7 $8 $9
but this is less than elegant. Would would be the "proper" way?
you can do "slicing" as well, $@ gets all the arguments in bash.
echo "${@:2}"
gets 2nd argument onwards
eg
$ cat shell.sh
#!/bin/bash
echo "${@:2}"
$ ./shell.sh 1 2 3 4
2 3 4
echo "${@:2}" would work properly when called with ./shell.sh 1 2 "multi-word argument" 4 5).
"${@:start:len}"
${@:2} is empty?Store $1 somewhere, then shift and use $@?
script1.sh:
#!/bin/bash
echo "$@"
script2.sh:
#!/bin/bash
shift
echo "$@"
$ sh script1.sh 1 2 3 4
1 2 3 4
$ sh script2.sh 1 2 3 4
2 3 4
$@ (e.g. echo "$@") to avoid weird parsing. See "I just assigned a variable, but echo $variable shows something else" and "When should I double-quote a parameter expansion?"