Javascript Multidimensional array

Question

I am trying to push the values [100,1000,10000,200,2000,20000,300,3000,30000] inside the multidimensional array in Javascript.

Multidimensional array should look like below

[[100,1000,10000],[200,2000,20000],[300,3000,30000]]

I am using the below code

var j = 0;
var x = 0;
var z = 0;
var f = new Array();

var rows = [100, 1000, 10000, 200, 2000, 20000, 300, 3000, 30000];
for (var i = 1; i <= rows.length; i++) {
    if (j < i) {
        f[x] = new Array();

        var arrval = parseInt(rows[j]);
        f[x][z] = arrval;
        z++;

        if (i % 3 == 0) {
            x++;
            z = 0;
        }
        j++;
    }
}

But the push into multidimensional array push seems to be not working. The final output is looking like [[,,10000],[,,20000],[,,30000]]

Could you please help?

Thanks in advance

argentum47 · Accepted Answer · 2014-05-25 06:26:09Z

4

Try this:

 var rows = [100, 1000, 10000, 200, 2000, 20000, 300, 3000, 30000];
    var newarr = new Array();
    /*for(var i =0; i< rows.length; i++){
        newarr.push(rows.splice(0,3));
    }
    console.log(newarr);*/

    while(rows.length){
       newarr.push(rows.splice(0,3)); 
    }

You can even make a function that would receive the number of columns as parameters.

function(orArr, nArr, cols){
    for(var i =0; i< orArr.length; i++){
    nArr.push(rows.splice(0,cols));
}

Update

: You should actually use slice() instead of splice() . as your original array would be modified if you are using splice(); In that case your code would be:

var newarr = new Array();
for(var i =0; i< rows.length; i++){
        newarr.push(rows.slice(0,3));
}
console.log(newarr);

edited May 25, 2014 at 6:26

answered May 23, 2014 at 10:26

argentum47

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Comments

woverton · Accepted Answer · 2014-05-23 10:13:14Z

2

You are clearing f[x] each iteration!

Here is a fix :)

var rows = [100,1000,10000,200,2000,20000,300,3000,30000];

var x=0; var z=0; var f = new Array();
for (var i=1;i<=rows.length;i++) {
    if(!f[x]){
        f[x]=new Array();
    };

    f[x][z]=parseInt(rows[i-1]);

    z++;
    if(i%3==0)
    {
        x++;
        z = 0;
    }
}

answered May 23, 2014 at 10:13

woverton

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Comments

kidwon · Accepted Answer · 2014-05-23 10:23:51Z

1

Here's another way to do it with a single loop http://jsfiddle.net/rene3/

var f = [];

var rows = [100, 1000, 10000, 200, 2000, 20000, 300, 3000, 30000];

for (var i = 0, len = rows.length; i < len ; i++) {
    if( !(i%3) ){
       f.push([]);
    }
    f[Math.floor(i/3)].push(rows[i])
}

answered May 23, 2014 at 10:23

kidwon

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Comments

MattJ · Accepted Answer · 2017-01-23 21:09:36Z

1

var f = [];

f.push([[100,1000,10000],[200,2000,20000],[300,3000,30000]]);

if there should be a dynamic loop, you could try:

var f = [];
var MyVal = n; // n = any value you like
var Val100, Val1000, Val10000;

for (var i=1; i<MyVal+1; i++){

Val100 = i*100;
Val1000 = i*1000;
Val10000 = i*10000;

f.push([Val100,Val1000,Val10000]);

}

answered Jan 23, 2017 at 21:09

MattJ

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Comments

Moob · Accepted Answer · 2014-05-23 10:18:29Z

0

var f = new Array(),
    x = 0,
    rows = [100, 1000, 10000, 200, 2000, 20000, 300, 3000, 30000];

for (var i = 0; i < rows.length; i++) {
    var a;
    if (i % 3 == 0) {
        f[x] = new Array();
        a = f[x];
        x++;
    }
    a.push(rows[i]);
}

http://jsfiddle.net/3R35Q/

answered May 23, 2014 at 10:18

Moob

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