replace data in array with str_replace function

Question

i have an array named $data

$data = array(
                    'word1'=>'Šššš',
                    'word2'=>'Zzzzžzzž',
                    'word3'=>'Āāāa'
                    );

what i want to do is to create new array with the same keys but with different values, so my new array would look like this:

$newdata = array(
                    'word1'=>'Ssss',
                    'word2'=>'Zzzzzzzz',
                    'word3'=>'Aaaa'
                    );

all i want to do is to replace letters with diacritical mark to normal letter, i have searched for php functions and i have understood that i could use str_replace function like this:

$search  = array('Ā', 'ā', 'Š', 'š', 'Ž', 'ž');
$replace = array('A', 'a', 'S', 's', 'Ž', ž);
str_replace($search, $replace, $data);

but how can i loop through array checking and replacing values without touching keys? or i cannot do that?(all data have to be be checked)

To transliterate a string like that, look into iconv and/or php.net/manual/en/class.transliterator.php rather than re-inventing the ICU library. — Denis de Bernardy
– Denis de Bernardy, Commented May 8, 2014 at 13:10

shatheesh · Accepted Answer · 2014-05-08 13:17:29Z

1

Try this

function splReplace($string)
{
    $search  = array('Ā', 'ā', 'Š', 'š', 'Ž', 'ž');
    $replace = array('A', 'a', 'S', 's', 'Ž', ž);
    return str_replace($search, $replace, $string);
}

$data = array(
                'word1'=>'Šššš',
                'word2'=>'Zzzzžzzž',
                'word3'=>'Āāāa'
                );

$data = array_map('splReplace',$data)   ;

answered May 8, 2014 at 13:17

shatheesh

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1 Comment

mickmackusa Over a year ago

str_replace() does not require a loop. It will happily traverse a 1d array.

Oscar M. · Accepted Answer · 2014-05-08 13:38:46Z

1

The third parameter, $subject for the str_replace function can be an array. So no need to loop through the values yourself. Tested on php 5.5, it'll keep your keys and values intact

$search  = array('Ā', 'ā', 'Š', 'š', 'Ž', 'ž');
$replace = array('A', 'a', 'S', 's', 'Z', 'z');

$data = array(
            'word1'=>'Šššš',
            'word2'=>'Zzzzžzzž',
            'word3'=>'Āāāa'
);

$data = str_replace($search, $replace, $data);

answered May 8, 2014 at 13:38

Oscar M.

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Comments

Awlad Liton · Accepted Answer · 2014-05-08 13:10:25Z

0

try like this:

 $data = array(
    'word1'=>'Šššš',
    'word2'=>'Zzzzžzzž',
    'word3'=>'Āāāa'
);

$search  = array('Ā', 'ā', 'Š', 'š', 'Ž', 'ž');
$replace = array('A', 'a', 'S', 's', 'Ž', 'ž');
$data2 = array();
foreach($data as $k =>$v){
    $data2[$k] = str_replace($search, $replace, $data[$k]);
}
print_r($data2);

you can change the line inside foreach by this:

$data2[$k] = str_replace($search, $replace, $v);

demo

answered May 8, 2014 at 13:10

Awlad Liton

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5 Comments

Awlad Liton Over a year ago

check out the demo @Xatenev

xate Over a year ago

Ah i see, why is it acting like this? Normally [] is creating a new element. In my thoughts - you would override $data2['KEY'] with each element again?

xate Over a year ago

Not from me .. anyways.. Can you give an answer on my question?^^

Awlad Liton Over a year ago

it is new array $data2

mickmackusa Over a year ago

str_replace() does not require a loop. It will happily traverse a 1d array.

Gwenc37 · Accepted Answer · 2014-05-08 13:14:32Z

0

with a simple foreach

<?php
$search  = array('Ā', 'ā', 'Š', 'š', 'Ž', 'ž');
$replace = array('A', 'a', 'S', 's', 'Ž', ž);
foreach($data as $key => $value){
    $data[$key] = str_replace($search, $replace, $data[$key]);
}
?>

edited May 8, 2014 at 13:14

answered May 8, 2014 at 13:09

Gwenc37

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1 Comment

mickmackusa Over a year ago

str_replace() does not require a loop. It will happily traverse a 1d array.

EquinoxMatt · Accepted Answer · 2014-05-08 13:19:01Z

0

A foreach works well

    $data = array(
                'word1'=>'Šššš',
                'word2'=>'Zzzzžzzž',
                'word3'=>'Āāāa'
                );

    $search  = array('Ā', 'ā', 'Š', 'š', 'Ž', 'ž');
    $replace = array('A', 'a', 'S', 's', 'Ž', ž);      

    foreach($data as $k => $v) { // for each element in $data
        $data[$k] = str_replace($search, $replace, $v); // do replacement and assign back to the array.
    }

    print "<pre>"; print_r($data); print "</pre>"; // print formatted array

edited May 8, 2014 at 13:19

answered May 8, 2014 at 13:13

EquinoxMatt

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1 Comment

mickmackusa Over a year ago

str_replace() does not require a loop. It will happily traverse a 1d array.

Community · Accepted Answer · 2023-11-17 20:33:26Z

0

To answer your question you can use a foreach with a reference:

$search  = array('Ā', 'ā', 'Š', 'š');
$replace = array('A', 'a', 'S', 's');
foreach ($data as &$word) {
    $word = str_replace($search, $replace, $word);
}

However, an easier way would to use a foreach with normalizer_normalize:

foreach ($data as &$word) {
    $word = normalizer_normalize($word);
}

or using array_map:

$data = array_map('normalizer_normalize', $data);

Please note that normalizer_normalize was added to the core in PHP 5.3, but in most linux distributions it isn't active by default.

You can also try out iconv():

foreach ($data as &$word) {
    $word = iconv('UTF-8', 'ASCII//TRANSLIT', $word);
}

edited Nov 17, 2023 at 20:33

CommunityBot

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answered May 8, 2014 at 13:23

Tim F

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1 Comment

mickmackusa Over a year ago

str_replace() does not require a loop. It will happily traverse a 1d array.

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