having trouble using variable variables in PHP

Question

i'm doing this code from the book and i can't seem to get it to work

<html>
<head> <h3> <u> PHP tutorials  </u> </h3> </head>
<body>

<?php

$Texas = "large";
$RhodeIsland = "small";

$statement = "Texas";
echo "$statement is $($statement)<br>";

$statement = "RhodeIsland";
echo "$statement is $($statement)<br>";

?>
</body>
</html>

this is the output i keep getting:

Texas is $(Texas)

RhodeIsland is $(RhodeIsland)

instead of:

Texas is large

RhodeIsland is small

Try to avoid use of this (variable variable) if possible.

The Alpha
– The Alpha

2014-04-26 05:43:09 +00:00
Commented Apr 26, 2014 at 5:43 — The Alpha
– The Alpha, Commented Apr 26, 2014 at 5:43

Amal · Accepted Answer · 2014-04-26 05:39:46Z

3

The syntax is : ${$variable_name}, not $($variable_name). You need to change your code to:

$statement = "Texas";
echo "$statement is ${$statement}<br>";

See the PHP manual documentation on Variable Variables for more information.

Demo

answered Apr 26, 2014 at 5:39

Amal

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Comments

Geo · Accepted Answer · 2014-04-26 05:44:28Z

0

There you go:

 <?php

    $Texas = "large";
    $RhodeIsland = "small";

    $statement = "Texas";
    echo $statement." is ".${$statement}."<br />";

    $statement = "RhodeIsland";
    echo $statement." is ".${$statement} ."<br />";

    ?>

answered Apr 26, 2014 at 5:44

Geo

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1 Comment

Amal Over a year ago

The OP was asking how to do it with variable variables, specifically. I assume he's trying to learn how it works :)

vastlysuperiorman · Accepted Answer · 2014-04-26 05:44:54Z

0

You should be using curly brackets instead of parentheses.

$statement = "RhodeIsland";
echo "$statement is ${$statement}<br>";

PHP documentation on the subject is here: http://www.php.net/manual/en/language.variables.variable.php

answered Apr 26, 2014 at 5:44

vastlysuperiorman

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Comments

Sahil Sarpal · Accepted Answer · 2014-04-26 07:01:20Z

0

this works :)

    <?php
    $Texas = "large";
    $RhodeIsland = "small";

    $statement = "Texas";
    echo $statement." is ".$$statement."<br>";

    $statement = "RhodeIsland";
    echo $statement." is ".$$statement."<br>";

answered Apr 26, 2014 at 7:01

Sahil Sarpal

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