How to insert HTML tag in Python?

Question

I have a class like this, that generates hyperlinks:

class getLink(obj):
    def __init__(self, text, url):
        self.text = self.Argument(text)
        self.url = self.Argument(url)
    def render(self, context):
        return "%s %s" % (html.link(self.text(context), self.url(context)))


def link(text, url):
    return mark_safe('<a href="%s">%s</a>' % (url, title))

Then to get a Link I do thus:

getLink(text=_('Test'),fn.getUrl())

HTML result:

<a href="/python/tests/">Test</a>

I want to wrap the link inside a <div> and another inside a <li> tag. I tried to add the tags directly in getLink() but doesn't work getLink("<div>" + text=_('Test'),fn.getUrl() + "</div>"). I'm newbie in Python so sorry if I'm wrong.

Thanks for you help!

getLink("<div>" + text=_('Test'),fn.getUrl() + "</div>") is invalid syntax in Python. — 2rs2ts
– 2rs2ts, Commented Apr 21, 2014 at 17:22

Talanor · Accepted Answer · 2014-04-21 17:17:16Z

3

I hardly understand where your code is from and if you are able to modify it.

But if you are, why not change the link function and wrap the link directly in there?

Like this :

def link(text, url):
    return mark_safe('<div><a href="%s">%s</a></div>' % (url, title))

Maybe you should be more explicit.

answered Apr 21, 2014 at 17:17

Talanor

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1 Comment

Mustapha Aoussar Over a year ago

Thank you for answer! but I want to wrap the link inside a <div> and another inside a <li> tag without creating another method or class. With your solution I can not change the tag <div> to another tag.

2rs2ts · Accepted Answer · 2014-04-21 17:25:06Z

1

Just wrap the result of your function call in the tags you want?

wrapped_in_div = "<div>" + getLink(text=_('Test'),fn.getUrl()) + "</div>"
wrapped_in_li = "<li>" + getLink(text=_('Test'),fn.getUrl()) + "</li>"

Or you can make use of format:

wrapped_in_div = "<{0}>{1}</{0}>".format("div", getLink(text=_('Test'),fn.getUrl()))
wrapped_in_li = "<{0}>{1}</{0}>".format("li", getLink(text=_('Test'),fn.getUrl()))

answered Apr 21, 2014 at 17:25

2rs2ts

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Comments

sabarin3 · Accepted Answer · 2019-02-20 13:23:04Z

0

@app.route('/')
def googlelink():
    return ('<div><a href="%s">%s</a></div>' % ("https://www.google.com","Google"))

answered Feb 20, 2019 at 13:23

sabarin3

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