Convert function string argument into variable

Question

I want to convert function string argument into array. so if I set 'user' than eventually in function I want to convert it to $user as soon as function start.

function

function get_item($object, $key)
{
    //I want to convert 'user' string in '$user' variable

    echo empty($object->$key) ? 'do_stuffs' : 'dont_do_stuffs';
}

usage

get_item('user', 'id');

I have tried something like

function get_item($object, $key)
{
    $$object = $object //this is not working

    echo empty($object->$key) ? 'do_stuffs' : 'dont_do_stuffs';
}

xdazz · Accepted Answer · 2014-04-15 09:56:53Z

1

Try the below:

function get_item($object, $key) {
  // if there are no other code in this function, then `$$object` will not be defined.
  // you can't get $user from the outside the function scope.
  $value =  $$object->{$key};
  echo empty($value) ? 'do_stuffs' : 'dont_do_stuffs';
}

You are using variable variables, in most case, it's not a good idea.

answered Apr 15, 2014 at 9:56

xdazz

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3 Comments

xdazz Over a year ago

@JatinSoni See my comment.

Code Lover Over a year ago

I see. Actually I am trying to get an object from outside the function. So this means it will not work? but when I passed variable itself $user it is working without any error

xdazz Over a year ago

@JatinSoni Yes, you have to pass it to the function, or using global variable (which is strongly not recommended.)

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