jquery inside javascript function to hide div array

Question

I am using jquery inside the javascript function to hide & show div. I need to show only div "Area" while hide other div

This one works, when i directly put the name of the div to hide & show :---

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js">
</script>

<script>

function area_visible()
{


  $('.Area').show();
  $('.Area-1').hide();
  $('.Area-2').hide();
  $('.Area-3').hide();


}

This one does not works if i try to access using array of div class, even alert message is not displayed 4 times for loop :----

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js">
</script>

<script>

var area_id = [
    "Area" , "Area-1", "Area-2", "Area-3"
];



function area_visible()
{

  $(area_id).each(function(index, element) {
        if(element != area_id[0] )
        {
          $("#" + element).hide();
        }
      alert('11');
    });


}

Please suggest. How to hide and show div by taking there name from an array (and i want to use jquery inside javascript function) ?

in the first example you are addressing them as classes, and in the second you are addressing them as though they are element IDs. Which are they? — Pow-Ian
– Pow-Ian, Commented Apr 11, 2014 at 12:22

Anton · Accepted Answer · 2014-04-11 12:20:13Z

3

Change

$("#" + element).hide();

to

$("." + element).hide();

You are trying to target an ID you must use . to target class.

answered Apr 11, 2014 at 12:20

Anton

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2 Comments

CodingIntrigue Over a year ago

I saw the first answer and was thoroughly confused :p

Anton Over a year ago

@RGraham haha i confused myself for a second there too so i deleted it for a second ^^

zerzer · Accepted Answer · 2014-04-11 12:22:08Z

1

in your first function you are using class $('.Area-1') and the second function you are selecting with ID $("#"+element)

so the fix is easy just change '#' to '.' in the second function

answered Apr 11, 2014 at 12:22

zerzer

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Comments

Jai · Accepted Answer · 2014-04-11 12:24:45Z

0

You have to change your id selector to a class selector and initiate the function:

$("." + element).hide(); // for your second function.

and initialize your func:

area_visible(); // for both it will work.

answered Apr 11, 2014 at 12:24

Jai

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